The probability is P = 0.004, so the correct option is D.
<h3 /><h3>How to find the probability?</h3>
We want to find the probability that 4 students lie on these 30% subgroup.
We know that there are 30 students, the 30% of 30 is:
x = (30%/100%)*30 = 9
So 9 out of 30 students prefer the tests to be on Mondays.
The probability that the first randomly selected kid wants the test to be on Monday is:
p= 9/30
For the next kid, the probability is:
p'= 8/29 (because one kid was already selected).
For the next one:
p'' =7/28
For the final one:
p''' =6/27
The joint probability is the product of these 4:
P = (9/30)*(8/29)*(7/28)*(6/27) = 0.004
So the correct option is D.
If you want to learn more about probability:
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Answer:
a) 48.21 %
b) 45.99 %
c) 20.88 %
d) 42.07 %
e) 50 %
Note: these values represent differences between z values and the mean
Step-by-step explanation:
The test to carry out is:
Null hypothesis H₀ is μ₀ = 30
The alternative hypothesis m ≠ 30
In which we already have the value of z for each case therefore we look directly the probability in z table and carefully take into account that we had been asked for differences from the mean (0.5)
a) z = 2.1 correspond to 0.9821 but mean value is ubicated at 0.5 then we subtract 0.9821 - 0.5 and get 0.4821 or 48.21 %
b) z = -1.75 P(m) = 0.0401 That implies the probability of m being from that point p to the end of the tail, the difference between this point and the mean so 0.5 - 0.0401 = 0.4599 or 45.99 %
c) z = -.55 P(m) = 0.2912 and this value for same reason as before is 0.5 - 0.2912 = 0.2088 or 20.88 %
d) z = 1.41 P(m) = 0.9207 0.9207 -0.5 0.4207 or 42.07 %
e) z = -5.3 P(m) = 0 meaning there is not such value in z table is too small to compute and difference to mean value will be 0.5
d) z= 1.41 P(m) =
Answer:17.1
Step-by-step explanation:
