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6 months ago

please help! functions and relations. f(x)= square root of x-4. find the inverse of f(x) and it’s domain.

Mathematics

1 answer:

likoan [24]6 months ago

4 0

ANSWER:

$\:D.\text{ }f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge-4$

STEP-BY-STEP EXPLANATION:

We have the following equation:

$f(x)=\sqrt{x}-4$

The inverse is the following (we calculate it by replacing f(x) by x and x by f(x)):

$\begin{gathered} x=\sqrt{f^{-1}(x)}-4 \\ \\ \sqrt{f^{-1}(x)}=x+4 \\ \\ f^{-1}(x)=(x+4)^2 \end{gathered}$

The domain would be the range of the original equation, and it would be the range of values that f(x) could take, which was from -4 to positive infinity, that is, f(x) ≥ -4.

Therefore, the domain is x ≥ -4.

So the correct answer is D.

$\:f^{-1}\left(x\right)=\left(x+4\right)^2;x\ge -4$

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2 years ago

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Option 4

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Steps to get the inverse of the given function,

Step 1,

Convert the function into equation,

$y=2\frac{1}{2}-3\frac{1}{3}x$

Step 2,

Interchange the variables 'x' and 'y',

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Step 3,

Solve the equation for the value of y,

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Step 4,

Convert the equation into inverse function,

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