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klio [65]
3 years ago
15

Helen's preferences over cds (c) and sandwiches (s) are given by u(s,

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0
<span>The fact that Helen’s indifference curves touch the axes should immediately make you want to check for a corner point solution. To see the corner point optimum algebraically, notice if there was an interior solution, the tangency condition implies (S + 10)/(C +10) = 3, or S = 3C + 20. Combining this with the budget constraint, 9C + 3S = 30, we find that the optimal number of CDs would be given by 3018â’=Cwhich implies a negative number of CDs. Since it’s impossible to purchase a negative amount of something, our assumption that there was an interior solution must be false. Instead, the optimum will consist of C = 0 and Helen spending all her income on sandwiches: S = 10. Graphically, the corner optimum is reflected in the fact that the slope of the budget line is steeper than that of the indifference curve, even when C = 0. Specifically, note that at (C, S) = (0, 10) we have P C / P S = 3 > MRS C,S = 2. Thus, even at the corner point, the marginal utility per dollar spent on CDs is lower than on sandwiches. However, since she is already at a corner point with C = 0, she cannot give up any more CDs. Therefore the best Helen can do is to spend all her income on sandwiches: ( C , S ) = (0, 10). [Note: At the other corner with S = 0 and C = 3.3, P C / P S = 3 > MRS C,S = 0.75. Thus, Helen would prefer to buy more sandwiches and less CDs, which is of course entirely feasible at this corner point. Thus the S = 0 corner cannot be an optimum]</span>
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4.645 rounded to the nearest whole number = 5

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V=basearea times 1/3 times height
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basearea=circle=pir^2
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How do you solve 58 and 1/3÷6 and 2/3
strojnjashka [21]

Answer:

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Step-by-step explanation:

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175/3 & 20/3

To divide fractions, I like to use a method called Keep Change Flip. Basically, you keep the first fractions the same, then change the sign. The division sign changes into a multiplication symbol. Now, your equation should look like this: 175/3 x 20/3. Next, flip the fraction from 20/3 into 3/20. This is what your equation should look like now: 175/3 x 3/20. Now you can multiply the fractions together. Before you do so, you can cross reduce to make it easier. What is a number that both 3 and 3 can be divided by? The correct answer is 3. 3/3= 1, so the equation is now 175/1 x 1/20. However, you can continue to cross reduce. You can also divide 175 and 20 by 5, so the equation changes into this: 35/1 x 1/20. Multiply numerator by numerator, denominator by denominator. So, the answer is 35/4, or 8 3/4 as a mixed number. Hope this helped!

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3 years ago
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