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Paha777 [63]
3 years ago
6

What is the slope of the line determined by the points (-1,2) and (6,-3) ?

Mathematics
1 answer:
Ilya [14]3 years ago
6 0
m=\dfrac{y_2-y_1}{x_2-x_1}\\\\
m=\dfrac{2-(-3)}{-1-6}\\
m=\dfrac{5}{-7}\\
m=-\dfrac{5}{7}\\
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zysi [14]

Answer:

CI = (70.861 , 94.418)

Step-by-step explanation:

In order to determine the 90% confidence interval you use the following formula (for a population approximately normal):

CI=(\overline{x}-Z_{\alpha/2}\frac{\sigma}{\sqrt{n}},\overline{x}+Z_{\alpha/2}\frac{\sigma}{\sqrt{n}})    (1)

\overline{x}: mean = 82.64

σ: standard deviation = 14.32

n: sample = 4

α: tail area = 1 - 0.9 = 0.1

Z_α/2 = Z_0.05: Z factor =  1.645

You replace these values and you obtain:

Z_{0.05}(\frac{14.32}{\sqrt{4}})=(1.645)(\frac{14.32}{\sqrt{4}})=11.778

The confidence interval will be:

CI=(82.64-11.778,82.64+11.778)=(70.861,94.418)

The 90% confidence interval is (70.861 , 94.418)

6 0
3 years ago
What is the lcm for 12,27,36​
Verdich [7]

\bold{Hey \ there!}\\ \bold{-  \ LCM\ means\ \ Lowest\ Common\ Multiple} \\ \\ \bold{So,\ the\ LCM\ of\ 12,27,36\ is\downarrow}

\bold{12: 2^3\times3} \\ \bold{27:3^3\ or \ you\ could\ say:3*3*3}\\ \bold{36:2^2 \times3^2}

\italics{Note: just\ factor\ them\ out\ to\ find\ the\ LCM!}

\boxed{\boxed{\bold{Answer:108}}}\checkmark

\bf{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}

\frak{LoveYourselfFirst:)}

3 0
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Answer:

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Step-by-step explanation:


6 0
3 years ago
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Your answer, in your set notation, is
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Answer:

\sf{(x-y)^2-a(y-x)} \\ = \sf{({x}^{2}  - 2xy +  {y}^{2} ) - (ay - ax)} \\

7 0
2 years ago
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