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pshichka [43]
1 year ago
7

Charlie has $3.15 in his bank which contains only nickels and dimes. There are 9 more nickels than dimes. Find the number he has

of each kind.
Mathematics
1 answer:
Brrunno [24]1 year ago
6 0

Charlie has $3.15 in his bank which contains only nickels and dimes. There are 9 more nickels than dimes. Then Number of dimes =18

and Number of nickels =27

<h3>What is basic algebra ?</h3>

Mathematical expressions can be used to depict situations or issues, and algebra is the field of mathematics that does this. For a mathematical expression to have meaning, it needs to include variables like x, y, and z as well as mathematical operations like addition, subtraction, multiplication, and division. Algebra is used in every area of mathematics, including coordinate geometry, calculus, and trigonometry. A straightforward algebraic expression is 2x + 4 = 8.

Given that : Charlie has $3.15 in his bank which contains only nickels and dimes. There are 9 more nickels than dimes

Let d be the number of dimes

d + 9 = Number of nickels

A dime = 0.1

nickle is = 0.05

0.1d + 0.05d + 0.45 = 3.15

0.15d = 2.7

d = 18

Number of dimes =18

Number of nickels = 18 + 9

=27

To learn more about basic algebra visit :

brainly.com/question/15167098

#SPJ13

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One member of the debate team is going to be chosen president. each member is equally likely to be chosen. the probability that
inessss [21]
Let
x-------> <span>the probability that a boy is chosen
B------> </span>number of boys in the debate team
G------> number of girls in the debate team<span>

we know that
B+G=20-----> G=20-B-----> equation 1
</span>probability that a boy is chosen=number of boys in the debate team/total of people
so
x=B/20-------> equation 2

t<span>he probability that a girl is chosen is 2/3 the probability that a boy is chosen
</span>probability that a girl is chosen=(2/3)*x
probability that a girl is chosen=G/20
(2/3)*x=G/20-----> equation 3
substitute equation 1 in equation 3
(2/3)*x=[20-B]/20----> equation 4

resolve the equations system
x=B/20
(2/3)*x=[20-B]/20

using a graph tool
see the attached figure
the solution is
x=0.6
B=12
G=20-12-----> G=8

number of boys in the debate team is 12
number of girls in the debate team is 8
the probability that a boy is chosen is 0.6 ----> 60%
the probability that a girl is chosen is 0.6*(2/3)----> 0.4---> 40%

the answer is
number of girls in the debate team is 8

7 0
3 years ago
In a large population of college-educated adults, the mean IQ is 118 with a standard deviation of 20. Suppose 200 adults from th
cricket20 [7]

Answer: 0.0793

Step-by-step explanation:

Let the IQ of the educated adults be X then;

Assume X follows a normal distribution with mean 118 and standard deviation of 20.

This is a sampling question with sample size, n =200

To find the probability that the sample mean IQ is greater than 120:

P(X > 120) = 1 - P(X < 120)

Standardize the mean IQ using the sampling formula : Z = (X - μ) / σ/sqrt n

Where;  X = sample mean IQ; μ =population mean IQ; σ = population standard deviation and n = sample size

Therefore, P(X>120) = 1 - P(Z < (120 - 118)/20/sqrt 200)

                                 = 1 - P(Z< 1.41)

The P(Z<1.41) can then be obtained from the Z tables and the value is 0.9207

Thus; P(X< 120) = 1 - 0.9207

                          = 0.0793

3 0
3 years ago
I forgot how to do most of this yet they gave it to me as hw ‍♀️
svp [43]

18.

-2(-9)+3

18+3

21

Explanation: -2(-9) When multiplying numbers that have both a negative sign, the answer is positive. Multiply normally.

19.

-6(-4)0

24(0)

0

Explanation: -6(-4) As I explained before, the answer would be positive.

24(0) Every number multiplied by 0 is 0.

20.

56+(-7)

49

Explanation: 56+(-7) Any problem like this is just basically going to be 56-7.

21.

-36+(-4)

-40

Explanation: -36+(-4) You are simply adding normally then adding the sign. This will only work if the signs are the same. (Signs are positive and negative.)

   

8 0
3 years ago
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11Alexandr11 [23.1K]
If it's a square all sides are 9 feet...9x9=81
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3 years ago
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