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zubka84 [21]
2 years ago
11

Solve please!!!!bbbbb

Mathematics
1 answer:
steposvetlana [31]2 years ago
4 0

1:1

one blue to one yellow. IT IS THAT EZ

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2b-3/b-2 = 3b/b+2 ... Solutions by cross multiplying
Rzqust [24]

Step-by-step explanation:

(2b-3)/(b-2)(b+2) = 3b(b-2)/(b+2)(b-2)

2b²+4b-3b-6/b²-4=3b²-6b/b²-4

2b²+b- 6= 3b²-6b

move square to square unknown to unknown

-b²+7b-6/b²-4

i also dk this is true or false

5 0
3 years ago
(4,?) is on the line below.  Find the other half of the coordinate. y= 2 7 x−3 y=27x-3
valina [46]
If you meant   y = 27x - 3, OK.    Then, if x = 4, y = 27(4) - 3, or 108-3 = 105.
8 0
3 years ago
QUESTION 2<br>Simplify the following<br>a5×a7​
Kryger [21]

Answer:

a^{12}

Step-by-step explanation:

<em><u>Identity Used </u></em>:   a^x \times a^y = a^{x+ y}

   

       a^5 \times a^7 = a^{5 + 7} = a^{12}

6 0
3 years ago
Read 2 more answers
10 Points<br> Can someone explain to me how to solve this
tatyana61 [14]

Answer:

d he didn't make a mistake

Step-by-step explanation:

so when is says comparing to one it means is the fraction greater than less than or equal to one and because 3/4 is less than one and 9/8 is greater than then 3/4 is less than 9/8 remember it always opens up to the larger number

8 0
2 years ago
Find two additional roots of P(x)=0.<br><br> 13+sqrt 3 and 7i
vova2212 [387]
So, x = 13, x = √3 and x =7i.

now, recall that for an EVEN radical, there are two possible roots, namely is say √3 is say hmmm some value "a", that means that a*a = √3, however, -a*-a is also √3, therefore, ±√3 are two valid values, and therefore -√3 is another one.

now.... keep in mind that, complex solutions or roots, never come all by their lonesome, their sister is always with them, the conjugate, so, for 7i or namely 0 + 7i, her sister is always around, 0 - 7i, which is the other root.
4 0
3 years ago
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