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denis-greek [22]
1 year ago
5

at an inter-species dance party, each cat danced with exactly three dogs and each dog danced with exactly two cats. no one dance

d with anyone of their own species, and twelve cats attended the party. how many dogs attended the party? (a) 8 (b) 12 (c) 16 (d) 18 (e) 24
Mathematics
1 answer:
stira [4]1 year ago
8 0

The correct option is (d) 18.

The number if dogs attended the inter-species dance party is 18.

<h3>What is combination?</h3>

A combination is an arithmetical technique for determining the number of different arrangements in a set of items in which the order of a selection is irrelevant. You can choose the items in just about any order in combinations.

  • Permutations and combinations are often confused. In permutations, however, the sequence of the selected items is critical.
  • For instance, the arrangements ab as well as ba are equal in combinations (regarded like one arrangement), but different in permutations.
  • Combinations are analyzed in combinatorics, but they are also used in other fields such as mathematics and finance.

Now, as per the given question.

If every cat danced with a 3 dogs, the total would be;

3 x 12 = 36 cat and dogs pairs.

Even so, every dogs just danced with 2 cat, implying that there had to be a mix-up. Then,

Number of dogs = 36/2 = 18

Therefore, the total number of dogs present in the inter-species dance party are 18.

To know more about the combinations, here

brainly.com/question/295961

#SPJ4

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