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1 year ago

If A = 3x2 + 3x - 6 and B = -2x2 - 6x + 7, thenA - B equals1) -5r- 11x + 132) 5r2 + 11x – 133) -5x2-x+14) 5x2 -*+1

Mathematics

1 answer:

Grace [21]1 year ago

5 0

$3x^2-(-2x^2)+5x-(-6x)-6-(7)=5x^2+11x\text{ - 13}$

Therefore, the correct answer is:

$2)5x^2+11x\text{ - 13}$

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What is the axis of symmetry of h(x)= 5x^2+40x+ 64?

andrezito [222]

Answer:

Axis of symmetry is x = -4

Step-by-step explanation:

h(x)= 5x^2+40x+ 64

Use the formula for axis of symmetry: x = -b/(2a)

Here, a = 5, b = 40, c = 64

x = -40/(2*5) = -40/10 = -4

Axis of symmetry is x = -4

3 0

3 years ago

Read 2 more answers

Angle $eab$ is a right angle, and $be = 9$ units. what is the number of square units in the sum of the areas of the two squares

Alla [95]

Let the measure of side AB be x, then, the measue of side AE is given by

$AE=\sqrt{9^2-x^2}$ .

Now, ABCD is a square of size x, thus the area of square ABCD is given by

$Area=x^2$

Also, AEFG is a square of size $\sqrt{9^2-x^2}$ , thus, the area of square AEFG is given by

$Area=\left(\sqrt{9^2-x^2}\right)^2=9^2-x^2=81-x^2$

<span>The sum of the areas of the two squares ABCD and AEFG is given by

$x^2+81-x^2=81$

Therefore, </span>the number of square units in the sum of the areas of the two squares <span>ABCD and AEFG is 81 square units.</span>

8 0

2 years ago

Determine whether the improper integral converges or diverges, and find the value of each that converges.

Ksju [112]

Answer:converge at $I=\frac{1}{3}$

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int^{\infty}_{3}\frac{1}{x^2}dx$

integration of $\frac{1}{x^2}$ is - $\frac{1}{x}$

$I=\left [ -\frac{1}{x}\right ]^{\infty}_3$

substituting value

$I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]$

$I=-\left [ 0-\frac{1}{3}\right ]$

$I=\frac{1}{3}$

so the value of integral converges at $\frac{1}{3}$

8 0

3 years ago

Find the area of a regular hexagon with a radius of 6 in

s344n2d4d5 [400]

Hexagon is a total of 6 triangle
Let find area of one triangle the multiplying with 6
Area of a triangle is A=1/2bh
We know b=6 and h= (6(square root of 3))/2
A= 1/2x6x(6(square root of3))/2=9(square root of 3)
Where square root of 3= 1.732
Area of a triangle=9x1.732 =15.588
Area of Hexagon equals 6 area of triangle so
Area of Hexagon= 6x 15.588=93.53

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3 years ago

An unfair coin with Pr[H] = 0.75 is flipped. If the flip results in a head, a student is selected at random from a class of si

Agata [3.3K]

Answer:

72.73% probability of selecting a girl, given the flip resulted inheads

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Coin resulted in heads

Student is selected at random from a class of six boys and sixteen girls.

Desired outcomes:

16 girls, so $D = 16$

Total outcomes:

16+6 = 22, that is, 22 students, so $T = 22$

Probability:

$P = \frac{16}{22} = 0.7273$

72.73% probability of selecting a girl, given the flip resulted inheads

7 0

3 years ago