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ELEN [110]
3 years ago
8

If Alberto's school is 3 miles due south of his house and 4 miles due west of Jimmy's house, what is the straight line distance

between Alberto's house and Jimmy's house?
Mathematics
2 answers:
Hoochie [10]3 years ago
5 0

using the Pythagorean Thereom:

3^2 +4^2 = X^2

9 +16 = 25

x^2 = 25

X = sqrt (25)

x = 5

 it would be 5 miles

Monica [59]3 years ago
3 0

Answer:

5 miles

Step-by-step explanation:

Going 3 miles due south and 4 miles due east (since school is 4 miles west of Jimmy's house, this means Jimmy's house is due east of the school) forms the legs of a right triangle.

To find the missing side length of a right triangle, we use the Pythagorean theorem:

a² + b² = c²

3² + 4² = c²

9 + 16 = c²

25 = c²

The opposite of "squared" is "square root":

√25 = √(c²)

5 = c

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If U = {x: X € N, 1 < × < 15)
Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

=  {2,4,6,8,10,12,14} U (  {3,6,9,12,15} n  {3,6,9,12,15} )

=  {2,4,6,8,10,12,14} U {3,6,9,12,15}

=  {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B)  =  ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

=  {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

=  {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)​

AU(BUC)

=  {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)​

=  ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)​

verifies

5 0
3 years ago
Solving systems of equations using substitution p=q+2<br> 4p+3q= -27
GREYUIT [131]
Ok, so you are given the value of P=q+2

The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27


Doing so will give us 4(q+2)+3q= -27

For right now, lets just focus on the first part, 4(q+2)

We can simplify this by distributing(multiplying) the 4 to whats inside the variables.

This will give us 4q+8

now lets add this back to the rest of the equation >>>  4q+8+3q = -27

We can further simplify by adding like terms >>> 7q+8 = -27

subtract the 8 from both sides >>> 7q = -35

now divide both sides by 7 >>> q = -35/7

Therefor q = -5

EDIT* 

now that we know q = -5 we can put q into the equation for P !

we know that p=q+2

so lets put q in now >>> p=(-5)+2

and simplify>>> p = -3

I hope this helps:)
6 0
4 years ago
Just 7 and 8 please!!
77julia77 [94]
Just multiply it so multiply 59.89 x 4 and then for number 8 multiply 88.70 x 4
4 0
4 years ago
Please helppppppppppppppppp
Alex777 [14]

Answer:

A

Step-by-step explanation:

6 0
3 years ago
If correct I will give brainly​
Marizza181 [45]

Answer:

B

Step-by-step explanation:

all you need to do is switch the x with 12

5 0
3 years ago
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