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wlad13 [49]
2 years ago
5

Can someone help me solve these problems?

Mathematics
1 answer:
Sonja [21]2 years ago
4 0

Answer:

2. A is false

   B is false

   C is false

   D is true

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kvasek [131]
6) p = 3.95 + 0.85t
7) e= 7.25n
8) p = 30 + 12w
9) f = 75 + 60h
10) d = 1 + 0.5h
11) j = 3x - 3, j = 3(5) - 3, j = 12
12) r = 4.25 + 1.50m
When m = 12, r = 4.25 + 1.50(12)
r = 4.25 + 18
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4 years ago
Find the product of 918.642 and 1/10​
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91.8642; multiplying by 1/10 is the same as dividing by 10. To divide a number by 10, you just move the decimal point one place to the left.

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4 years ago
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height of the gateway arch shown on the Missouri quarter is 630 feet or 7,560 inches. find how many 4-inch stacks of quarters ma
Bingel [31]
<span>The height of Gateway Arch shown on the Missouri quarter is 630 feet or 7,560 inches. Find how many 4 inch stacks of quarters make up the height of the Gateway Arch. If there are 58 quarter in 4 inch stack o, how many quarters high is the arch? </span>

<span>Hence to find how many 4 inch stacks of quarters make up the height of the </span><span>Gateway Arch, 

Since the Gateway Arch is 7560 then for every stack is 4 inches to find the stacks all in all, we just have to divide 7560 / 4 = 1890

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3 years ago
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The tangent to the circle x^2+y^2=18 is parallel to the tangent x+y=6
liubo4ka [24]

Answer:

y = -x - 6

Step-by-step explanation:

If we are looking for the equation of the line tangent to the circle, we have to find the first derivative of the circle function.  If that tangent line is to be parallel to the given tangent line, we need to find the slope of the the given tangent line and make sure the slope of the line we are looking for is the same.  First let's find the slope of the given tangent.  If the given tangent is x+y=6, then to find the slope, solve for y:

y = -x + 6.  So the slope of that line, and also the slope of the tangent we are solving for, is -1.  Hold that thought while we find the derivative of the function.  Using implicit differentiation, we find the derivative to be:

2x+2y\frac{dy}{dx}=0

Solving for the slope (dy/dx) gives us:

2y\frac{dy}{dx}=-2x and

\frac{dy}{dx}=\frac{-2x}{2y} so

\frac{dy}{dx}=-\frac{x}{y}

Subbing in the value of the slope we found:

-1=-\frac{x}{y} so

-y = -x or, equivalently,

y = x.  Now that we know that y and x are the same value, we can go back to the original circle to find out what they both are by substitution.  If y = x, we make the substution:

If x^2+y^2=18, then

y^2+y^2=18 and

2y^2=18 and

y^2=9 so

y = ±3

We will choose the negative root (you'll see why in a second) and sub that in for both y and x since y and x are th same number.  Going back to the fact that the slope is -1:

y - (-3) = -1(x - (-3)) simplifies a bit to:

y + 3 = -x - 3 which gives us, in slope-intercept form:

y = -x - 6

That is the equation of the tangent to the circle that is parallel to the given tangent.

If we would have chosen the principle (or positive) root of 3, our equation would have looked like this:

y - 3 = -1(x - 3) and

y = -x + 3 + 3 so

y = -x + 6.  Notice that that is the EXACT SAME EQUATION as the given tangent.  That's why we have to pick the negative 3 as our root.

Good luck in your calculus class!  Make sure you post your questions in here!  Many of us LOVE the challenge of calculus!

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