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2 years ago

The product of two consecutive odd numbers is 1023

Mathematics

1 answer:

devlian [24]2 years ago

3 0

31 and 33 are two consecutive odd numbers whose product is 1023

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Find the measure of each interior angle. Round to the nearest hundredth.

Butoxors [25]

Answer:

x = 76.80°

4x - 142 = 165.18°

x/5 = 15.36°

5x/9 + 60 = 102.66°

Step-by-step explanation:

Total angle in a quadrilateral is 360

x + 4x - 142 + x/5 + (5/9)x + 60 = 360

259x/45 + - 82 = 360

259x/45 = 442

x = 76.7953668

x = 76.80°

4x - 142 = 165.18°

x/5 = 15.36°

5x/9 + 60 = 102.66°

8 0

3 years ago

Challenge 5 Rani, Layla and Tash take part in a basketball competition. Rani scores 4 times as many baskets as Layla. Tash score

Murljashka [212]

Answer:

Step-by-step explanation:

r=4*l

t=r-8

t=4l-8

r+t+l=100

4l+4l-8+l=100

9l-8=100

+8 +8

9l=108

:9. :9

l=12 Layla score

4*12=48 Rani score

48-8=40 Tash score

verify 12+40+48=100 correct

4 0

3 years ago

How do I solve this

barxatty [35]

Answer:

it's 67

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The equation my daughter is trying to solve is: 25 × 8 × 4. The directions state "use properties to find the product. Explain yo

irinina [24]

Do pemdas and once you got your answer from that keep checking

5 0

2 years ago

The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the proba

zlopas [31]

Answer:

The probability that there are 8 occurrences in ten minutes is

option B. 0 .0771

Step-by-step explanation:

Given:

Random Variable = x

Mean number of occurrences in ten minutes is 5.3.

The probability of an occurrence is the same in any two time periods of an equal length

To Find:

The probability that there are 8 occurrences in ten minutes = ?

Solution:

Let X be the number of occurrences of the event X

$X \sim {Pois} (\lambda)$

$\lambda = E(X) = 5.3$

Possion of distribution is given by ,

$P(X=x) = \frac{e^{- \lambda} \lambda^{x}}{x!}$

Substituting the values,

$P(X=8) = \frac{e^{- 5.3} 5.3^{8}}{8!}$

$P(X=8) = \frac{(0.004994) ( 622596.904)}{40320}$

$P(X=8) = \frac{(3109.24894)}{40320}$

P(X=8) = 0.0771

3 0

2 years ago