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Simora [160]
3 years ago
13

Which formula can be used to find the math term of a geometric sequence where the first term is 8 and the common ratio is -3?

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0

a_n = 8(-3)^{n-1}

That would be the formula you would use.

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Plas help me with question 5
Arlecino [84]

Answer:

-1, 1, -1

Step-by-step explanation:

-1*-1*-1 = -1

1*-1 = -1

4 0
2 years ago
Given the following: P(A) =0.3 P(B) = 0.2 P(A OR B) = 0.5 P(A AND B) = 0 Which of the following is true?a. A and B are disjoint.
erastova [34]

Answer:

a. A and B are disjoint

Step-by-step explanation:

We know that P(A and B)=0, It means that event A and event B have nothing in common and it means that event A and event B are disjoints events.

The event A and event B are independent if

P( A and B)= P(A)*P(B)

P(A)*P(B)=0.3*0.2=0.06

So, P(A and B)≠P(A)*P(B)

Hence events A and B are not independent.

Option a is A and B are disjoints which is correct

Option b is A and B are neither disjoints nor independent which is partially false as A and B are disjoints event.

Option c states that A and B are independent which is clearly false.

Option d states that A and B are disjoints and independent which is partially false as A and B are not independent.

Hence the correct option is option A.

5 0
3 years ago
A new bank customer with $3,500 wants to open a money market account. The bank is offering a simple interest of 1.6%.
Bond [772]

Answer:

A is $490 and B is 3990

Step-by-step explanation:

The way I solved this is with my last brain cells, you welcome.

4 0
3 years ago
For what values of them will the expression below be a perfect square? <br> 9x^2+30x+m
matrenka [14]
I am so so so sorry I do not know the answer but I might later in the shool year
4 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
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