Answer:
b
Step-by-step explanation:
all squares have 4 sides which is a quadrilateral.
Answer:
C. sqrt((-3-6)² + (4+2)²)
Step-by-step explanation:
as we are using Pythagoras and asking for the distance as a side length (actually the Hypotenuse, the side opposite of the 90 degree angle) in a right-angled triangle, only an expression of a square root of a sum of squares can be right.
so, A and B are automatically out without even further analysis.
for the distance between 2 points on a coordination grid we build the mentioned right-angled triangle with the difference in x-direction as one side (e.g. "a"), the difference in y-direction as a second side (e.g. "b").
and the direct distance is then the Hypotenuse "c".
you remember Pythagoras :
c² = a² + b²
and therefore
c = sqrt(a² + b²)
in our example "a" is the difference between the 2 x-values.
a = (-3 - 6)
and "b" is the difference between the 2 y-values.
b = (4 - -2) = (4 + 2)
since we have to square them for the formula, the direction of what is subtracted from what is irrelevant, as the square of a negative value is also positive.
c = sqrt((-3 - 6)² + (4 + 2)²)
and that is answer option C
Sorry if this isn’t the right answer :(
A. 2 + 1 + 2 + 1 + 2 / 5 = 1.6
B. 4 + 4 + 4 + 4 / 4 = 4
Answer:
56
Step-by-step explanation:
The probability both spiners land on red: 0,5*0,6=0,3 (0,5 is A spine lands on red and 0,6 is B spiner lands on red)
The number of both spiners land on red is 84.
So we have:
X——>100%
84——->30%
X=8400/30
X=280
The total number of all spines A and B for onse.
The probability to both spiners land on blue is:
0,5*0,4=0,2 (0,5 is probabiliti to A lands on blue, 0,4 is B lands on blue)
The number of both spiners land on blue is:
280*0,2=56
