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Zielflug [23.3K]
3 years ago
5

​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If th

e distance is
68 cm when the weight is 2 ​kg, what is the distance when the weight is 5 ​kg?
Mathematics
1 answer:
zlopas [31]3 years ago
4 0
It would just be 2x68, in the sense that the original equation for Hooke's Law is F=kX. In your equation, w is k and X is D. the answer is 136cm for 2kg and 340cm  for 5kg. Tell me if this is wrong please.
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Answer:

∠D = 13°

Step-by-step explanation:

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Answer:

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To solve an equation or an inequality, you do the opposite operation in the opposite order.

Since the second operation was add 2/5, to solve, you start by doing the opposite of the second operation. That means you subtract 2/5 from both sides.

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