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Zielflug [23.3K]
3 years ago
5

​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If th

e distance is
68 cm when the weight is 2 ​kg, what is the distance when the weight is 5 ​kg?
Mathematics
1 answer:
zlopas [31]3 years ago
4 0
It would just be 2x68, in the sense that the original equation for Hooke's Law is F=kX. In your equation, w is k and X is D. the answer is 136cm for 2kg and 340cm  for 5kg. Tell me if this is wrong please.
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What is an equation of the line that passes through the points (-6, -2) and
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Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

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where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

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So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

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Step-by-step explanation:

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To find how many lbs 70 kg is, we do 70/0.453592 which is 154.3236.

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