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Zielflug [23.3K]
3 years ago
5

​Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If th

e distance is
68 cm when the weight is 2 ​kg, what is the distance when the weight is 5 ​kg?
Mathematics
1 answer:
zlopas [31]3 years ago
4 0
It would just be 2x68, in the sense that the original equation for Hooke's Law is F=kX. In your equation, w is k and X is D. the answer is 136cm for 2kg and 340cm  for 5kg. Tell me if this is wrong please.
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We will conclude that:

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<h3>Comparing the domains and ranges.</h3>

Let's study the two functions.

The exponential function is given by:

f(x) = A*e^x

You can input any value of x in that function, so the domain is the set of all real numbers. And the value of x can't change the sign of the function, so, for example, if A is positive, the range will be:

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For the logarithmic function we have:

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As you may know, only positive values can be used as arguments for the logarithmic function, while we know that:

\lim_{x \to \infty} ln(x) = \infty \\\\ \lim_{x \to0} ln(x) = -\infty

So the range of the logarithmic function is the set of all real numbers.

<h3>So what we can conclude?</h3>
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If you want to learn more about domains and ranges, you can read:

brainly.com/question/10197594

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