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xenn [34]
1 year ago
6

A) Work out (8 x 10') x (2 x 10*)

Mathematics
1 answer:
Amanda [17]1 year ago
4 0
The first answer is 1600 and I’m standard form is one thousand six hundred.
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Answer:

42

Step-by-step explanation:

i said so

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Find the value of x in the figure and choose the correct result,​
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3 years ago
Find k if (x+1) 2x^3+kx^2+1
Viktor [21]
<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

k = 1

<h2>Step-by-step explanation:</h2>

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

<em>This is because;</em>

i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.

ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

=> (-3)² - 9

=> (9) - 9 = 0

Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

2(-1) + k(1) + 1 = 0

-2 + k + 1 = 0

k - 1 = 0

k = 1

Therefore the value of k is 1.

3 0
3 years ago
PLEASE HELP ASAP!!!!!!!! What is the volume of the prism?
AURORKA [14]
Well the answer is 13 and cannot be written in simplest form because 1/2 and 1/2 have the same denominator so you add them together and you get 2/2 which is a whole number then you add the other whole numbers but don’t forget the new whole number then add the 5 and you get 13 cm
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3 years ago
A number b increased by 3 is greater than or equal to -26
photoshop1234 [79]

A number b increased by 3 is greater than or equal to -26:

b+3\geq-26\qquad\text{subtract 3 from both sides}\\\\\boxed{b\geq-29}

5 0
3 years ago
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