Question

25 POINTS!!!!

Answer 1

Hey there, Lets solve this problem together. 

You are given two lengths of a right angled triangle, so Pythagoras' theorem is the way to go. 

In algebraic terms, a² + b² = c² where c is the hypotenuse while a and b are the legs of the triangle. 

In a right angled triangle:
the square of the hypotenuse is equal to
the sum of the squares of the other two sides.

c² (the diagonal squared) = a² (one length squared) + b² (the other length squared)  

leg a and b are both 3 

$3^2 + 3^2 = c^2$

$= 3 * 3 = 3^2$

$= 9 + 9 = c^2$ 

$9 + 9 =18$ 

$18 = c^2$ 

The opposite of ^2 is ^1/2 also known as the square root

c = sqrt(18)

Solved = c≈4.24 

Answer 2

It will be square root of 6