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AfilCa [17]
1 year ago
12

Each of the following names is wrong. Draw structures based on them, and correct the names:(a) 3,3-dimethylbutane

Chemistry
1 answer:
Alex777 [14]1 year ago
8 0

The correct name of the given compound is 2,2-dimethylbutane .

The given compound is 3,3-dimethylbutane .

The given name is wrong according to the IUPAC nomenclature because the numbering of carbon atom in a ring should start from the carbon atom which is bonded to the functional group to give least numbering to the functional group .

Here in this case , there is only 4 carbon in the main chain . due to which the number only can assign to the functional group  is 1 and 2 . no other possibilities available . and also the functional group should be least numbered .

Hence , the correct name is 2,2-dimethylbutane .

<h3>IUPAC nomenclature :</h3>

it is a systematic way of nomenclature of organic compounds .

it is based on the position of functional groups , preference of the functional group , long or short chain of carbon , preference of double bond , single bond and triple bond , branching of carbon chain ,etc.

Learn more about nomenclature here:

brainly.com/question/14094007

#SPJ4

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1. Wildlife

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3 years ago
Why would the volume of one object calculated using “Measurement and Calculation” differ from the volume of the same object calc
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Answer:

Measuring the Volume of Solids

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8 0
3 years ago
Read 2 more answers
Electronic transitions (i.e., absorption of uv or visible light) of the conjugated molecule butadiene can be approximated using
dlinn [17]

Answer:

2.51 Angstroms

Explanation:

For a particle in a one dimensional box, the energy level, En, is given by the expression:

En = n²π² ħ² / 2ma²

where n is the energy level, ħ²  is Planck constant divided into 2π, m is the mass of the electron ( 9.1  x 10⁻³¹ Kg ), and a is the length of the one dimensional box.

We can calculate  the change in energy, ΔE, from n = 2 to n= 3  since we know the wavelength of the transition  ( ΔE = h c/λ ) and then substitute this value for the expresion of the ΔE for a particle in a box and solve for the  length a.

λ = 207 nm x 1 x 10⁻⁹ m/nm = 2.07 x 10⁻⁷ m      ( SI units )

ΔE = 6.626 x 10⁻³⁴ J·s x  3 x 10⁸ m/s  / 2.07 x 10⁻⁷ m

ΔE   = 9.60 x 10⁻¹⁹ J

ΔE(2⇒3) = ( 3 - 2 )  x  π² x ( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

9.60 x 10⁻¹⁹ J  =  π² x( 6.626 x 10⁻³⁴ J·s / 2π )² / ( 2 x 9.1 x 10⁻³¹ Kg x a² )

⇒ a = 2.51 x 10⁻¹⁰ m

Converting to Angstroms:

a = 2.51 x 10⁻¹⁰ m x 1 x 10¹⁰ Angstrom / m = 2.51 Angstroms

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Explanation:

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