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Tema [17]
3 years ago
9

Why would the volume of one object calculated using “Measurement and Calculation” differ from the volume of the same object calc

ulated using “Water Displacement.”
Chemistry
2 answers:
Mars2501 [29]3 years ago
8 0

Answer:

Measuring the Volume of Solids

Rectangular prism - Multiply the measurement of the length times the width, then times the height.

Cube - Since all sides are the same measurement, it would be the measurement of any side, or edge, cubed, or a³

Explanation:

Stells [14]3 years ago
4 0
Good job i agree with this answer ^
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Moon has to be in-between the Earth and the Sun.

2. Moon's umbra should sweep your place.

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3 years ago
NaOH(aq) + MgSO4(aq) →
Cerrena [4.2K]

Answer:

if balanced reaction then 2 NaOH + MgSO4 → Mg(OH)2 + Na2SO4

Explanation:

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A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm  ; Final Volume = 1.8 L ; Final pressure = 0.73 atm  

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T_2 ),

P_1V_1 / T_1 = P_2V_2 / T_2,

T_2 = P_2V_2T_1 / P_1V_1,

T_2 = 0.73 atm * 1.8 L * 298.15 K / 1 atm * 1.2 L = ( 0.73 * 1.8 * 298.15 / 1 * 1.2 ) K = 326.47425 K,

T_2 = 326.47425 K = 53.32425 C

7 0
3 years ago
600.0 mL of air is at 20.0 Celsius. What is the volume of the same air at 60.0 Celsius
REY [17]

Answer:

0.682L or 682mL

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T1 = 293K

V2=?

T2= 333K

Explanation:

?

6 0
3 years ago
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