6:8 = 3:4, 12:16, 18:24
24:18 = 4:3, 8:6, 12:9
15:10 = 3:2, 30:20, 45:30
<h2>1) B</h2>
<h2>2) C</h2>
<h2>3) A</h2>
<h3>do you need an explanation?</h3>
<em>The coordinates for each point would be:</em>
M': (2,-2)
N': (4, 2)
O': (8, -1)
If the rule is (x, y) = (x + 2, y - 6), this is how you solve this problem...
M to M': (0 + 2, 4 - 6), then (2, -2)
N to N': (2 + 2, 8 - 6), then (4, 2)
O to O': (6 = 2, 5 - 6), then (8, -1)
Answer:
0.2239
Step-by-step explanation:
Given that you have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a hat, then from that hat, I choose 3 balls, without replacing the balls between selections.
Either I or II hat can be selected.
Prob of selecting any one hat = 0.5
After selecting I hat, selecting 3 balls can be done in 15C3 ways and from II hat it can be done in 10C3 ways.
total no of ways of selecting 3 balls = (10+15)C3 = 2300
Probability required 