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luda_lava [24]
1 year ago
14

1 For each sequence of numbers: i write down the term-to-term rule. ii write the sequence of numbers in a table iii work out the

position-to-term rule iv check your rule works for the first three terms. a 3, 6, 9, 12, ..., ... b 3, 5, 7, 9, ..., ... c 3,9, 15, 21,...,..​
Mathematics
1 answer:
lions [1.4K]1 year ago
5 0

Answer:

wag puro brainly mag sumikap kayo heheheh

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Lily wants to buy a new smartphone. She has $500 to spend. List three ways she can get a good deal.
natta225 [31]

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  • get a coupon find a cheap on or steal it or get a discount
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4 years ago
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What are 3 equivalent ratios for 6:8, 24:18, and 15:10?
kicyunya [14]
6:8 =       3:4, 12:16, 18:24
24:18 =   4:3, 8:6, 12:9
15:10 =   3:2, 30:20, 45:30
3 0
3 years ago
HELP PLEASE ASAP:<
nataly862011 [7]
<h2>1) B</h2>

<h2>2) C</h2>

<h2>3) A</h2>

<h3>do you need an explanation?</h3>
4 0
2 years ago
PLEASE BE QUICK
-BARSIC- [3]

<em>The coordinates for each point would be:</em>

M': (2,-2)

N': (4, 2)

O': (8, -1)

If the rule is (x, y) = (x + 2, y - 6), this is how you solve this problem...

M to M': (0 + 2, 4 - 6), then (2, -2)

N to N':  (2 + 2, 8 - 6), then (4, 2)

O to O': (6 = 2, 5 - 6), then (8, -1)

7 0
3 years ago
have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a h
Pavel [41]

Answer:

0.2239

Step-by-step explanation:

Given that you have two hats. In one hat are balls numbered 1 through 15. In the other hat are balls numbered 16 through 25. I first choose a hat, then from that hat, I choose 3 balls, without replacing the balls between selections.

Either I or II hat can be selected.

Prob of selecting any one hat = 0.5

After selecting I hat, selecting 3 balls can be done in 15C3 ways and from II hat it can be done in 10C3 ways.

total no of ways of selecting 3 balls = (10+15)C3 = 2300

Probability required =\frac{0.5*15C3+0.5*10C3}{2300} \\=\frac{455+60}{2300} \\=0.2239

7 0
4 years ago
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