Answer:
3,
3x+5
Step-by-step explanation:
DIFFERENTIATE W.R.T. X
3
EVALUATE
3x+5
Answer:
the horizontal one
Step-by-step explanation:
Answer:
C. a quantity used as a standard measurement
Step-by-step explanation:
A unit is a universally acceptable system of measurement. The system is majorly referred to as the international standard of units i.e (SI) units.
Since physical quantities could be categorize as either fundamental or derived. The use of units in measurement is very essential, because it relates the magnitude measured to the physical quantity.
The units of measurement tells what physical quantity has been measured.
Answer:
At 95% confidence level, the difference between the proportion of freshmen using steroids in Illinois and the proportion of seniors using steroids in Illinois is -7.01135×10⁻³ <
< 1.237
Step-by-step explanation:
Here we are required to construct the 95% confidence interval of the difference between two proportions
The formula for the confidence interval of the difference between two proportions is as follows;
![\hat{p}_1-\hat{p}_2\pm z^{*}\sqrt{\frac{\hat{p}_1\left (1-\hat{p}_1 \right )}{n_{1}}+\frac{\hat{p}_2\left (1-\hat{p}_2 \right )}{n_{2}}}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D_1-%5Chat%7Bp%7D_2%5Cpm%20z%5E%7B%2A%7D%5Csqrt%7B%5Cfrac%7B%5Chat%7Bp%7D_1%5Cleft%20%281-%5Chat%7Bp%7D_1%20%20%5Cright%20%29%7D%7Bn_%7B1%7D%7D%2B%5Cfrac%7B%5Chat%7Bp%7D_2%5Cleft%20%281-%5Chat%7Bp%7D_2%20%20%5Cright%20%29%7D%7Bn_%7B2%7D%7D%7D)
Where:
![\hat{p}_1 = \frac{34}{1679}](https://tex.z-dn.net/?f=%5Chat%7Bp%7D_1%20%20%3D%20%5Cfrac%7B34%7D%7B1679%7D)
n₁ = 1679
n₂ = 1366
at 95% confidence level = 1.96
Plugging in the values, we have;
![\frac{34}{1679}- \frac{24}{1366} \pm 1.96 \times \sqrt{\frac{ \frac{34}{1679}\left (1- \frac{34}{1679}\right )}{1679}+\frac{\frac{24}{1366} \left (1-\frac{24}{1366} \right )}{1366}}](https://tex.z-dn.net/?f=%5Cfrac%7B34%7D%7B1679%7D-%20%5Cfrac%7B24%7D%7B1366%7D%20%5Cpm%201.96%20%5Ctimes%20%5Csqrt%7B%5Cfrac%7B%20%5Cfrac%7B34%7D%7B1679%7D%5Cleft%20%281-%20%5Cfrac%7B34%7D%7B1679%7D%5Cright%20%29%7D%7B1679%7D%2B%5Cfrac%7B%5Cfrac%7B24%7D%7B1366%7D%20%5Cleft%20%281-%5Cfrac%7B24%7D%7B1366%7D%20%20%20%5Cright%20%29%7D%7B1366%7D%7D)
Which gives;
-7.01135×10⁻³ <
< 1.237.
At 95% confidence level, the difference between the proportion of freshmen using steroids in Illinois and the proportion of seniors using steroids in Illinois = -7.01135×10⁻³ <
< 1.237.