Answer:
(1- cose0)(1 + cose0) = 0
(1-sin0)(1+sin0) = 1
Step-by-step explanation:
(1- cose0)(1 + cose0) = 0
1st Simplify: \left(1-cos(0))(1+cos(0))
2nd Use the following trivial identity: (0\right)=1
=(1-1)(1+1)
3rd Simplify:(1- cose0)(1 + cose0) = 0
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(1-sin0)(1+sin0) = 1
1st Use the following trivial identity: sin(0)=0
(1 - 0) (1 + 0)
2nd Simplify: (1-sin0)(1+sin0) = 1
Answer:
-4x^3 +12x^2 for 0 < x < 3
Step-by-step explanation:
The power rule is appropriate:
(d/dx)x^n = n·x^(n-1)
This is applied to each of the terms.
F'(x) = -(4·x^3) +4(3x^2) +0
F'(x) = -4x^3 +12x^2 . . . . for 0 < x < 3
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The derivative is not defined at the endpoints of the interval, so F'(x) is only defined on (0, 3), not [0, 3].
The expression ' one-half difference of a number cubed and one'. is written as \frac{1}{2}(x^3-1)
Step-by-step explanation:
Geometric Sequence formula for general term:
an = a1(r^n-1)
a1 = 4 × (-5)^1-1
a1 = 4
r = -5
Summation formula for geometric sequence :
Sn = a1 ( 1 - r^n / 1 - r )
...<em>take n from the top of the summation.</em>
= 4 ( 1 -(-5)^6 / 1 -(-5)
= -10416.
Answer:
I think its 1/3/ and 4. But I dont know tho. just make sure with other.
Step-by-step explanation: