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1 year ago

Do linear equations have 2 answers?

Mathematics

1 answer:

Alinara [238K]1 year ago

3 0

The Linear equations can have 2 or more answers if the lines overlap each other .

In the question ,

it is asked that can two linear equations have 2 answers or solutions .

We know that ,

(1) two linear equations can have No Solution / Zero Solution if two lines are parallel .

(2) two linear equations can have One Solution/Unique Solution if two line intersect at a point .

(3) two linear equations can have infinitely many solution if lines overlap on each other .

So from (3) , we can conclude that linear equations can have 2 or more solutions when the line are overlapping .

Therefore , Yes, the linear equations can have two answers .

Learn more about Linear Equations here

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What is the slope of the line represented by the equation y = 1/5x-3?

Romashka-Z-Leto [24]

Answer:

1/5

Step-by-step explanation:

Your equation is written in the form y=mx+b, where m is the slope and b is the y-intercept.

m=1/5, so the slope is 1/5

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3 years ago

A norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. Find the dimensions of a norman

Yanka [14]

Answer:

$W\approx 8.72$ and $L\approx 15.57$ .

Step-by-step explanation:

Please find the attachment.

We have been given that a norman window is constructed by adjoining a semicircle to the top of an ordinary rectangular. The total perimeter is 38 feet.

The perimeter of the window will be equal to three sides of rectangle plus half the perimeter of circle. We can represent our given information in an equation as:

$2L+W+\frac{1}{2}(2\pi r)=38$

We can see that diameter of semicircle is W. We know that diameter is twice the radius, so we will get:

$2L+W+\frac{1}{2}(2r\pi)=38$

$2L+W+\frac{\pi}{2}W=38$

Let us find area of window equation as:

$\text{Area}=W\cdot L+\frac{1}{2}(\pi r^2)$

$\text{Area}=W\cdot L+\frac{1}{2}(\pi (\frac{W}{2})^2)$

$\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W}{2})^2)$

$\text{Area}=W\cdot L+\frac{\pi}{2}(\frac{W^2}{4})$

$\text{Area}=W\cdot L+\frac{\pi}{8}W^2$

Now, we will solve for L is terms W from perimeter equation as:

$L=38-(W+\frac{\pi }{2}W)$

Substitute this value in area equation:

$A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2$

Since we need the area of window to maximize, so we need to optimize area equation.

$A=W\cdot (38-W-\frac{\pi }{2}W)+\frac{\pi}{8}W^2$

$A=38W-W^2-\frac{\pi }{2}W^2+\frac{\pi}{8}W^2$

Let us find derivative of area equation as:

$A'=38-2W-\frac{2\pi }{2}W+\frac{2\pi}{8}W$

$A'=38-2W-\pi W+\frac{\pi}{4}W$

$A'=38-2W-\frac{4\pi W}{4}+\frac{\pi}{4}W$

$A'=38-2W-\frac{3\pi W}{4}$

To find maxima, we will equate first derivative equal to 0 as:

$38-2W-\frac{3\pi W}{4}=0$

$-2W-\frac{3\pi W}{4}=-38$

$\frac{-8W-3\pi W}{4}=-38$

$\frac{-8W-3\pi W}{4}*4=-38*4$

$-8W-3\pi W=-152$

$8W+3\pi W=152$

$W(8+3\pi)=152$

$W=\frac{152}{8+3\pi}$

$W=8.723210$

$W\approx 8.72$

Upon substituting $W=8.723210$ in equation $L=38-(W+\frac{\pi }{2}W)$ , we will get:

$L=38-(8.723210+\frac{\pi }{2}8.723210)$

$L=38-(8.723210+\frac{8.723210\pi }{2})$

$L=38-(8.723210+\frac{27.40477245}{2})$

$L=38-(8.723210+13.70238622)$

$L=38-(22.42559622)$

$L=15.57440378$

$L\approx 15.57$

Therefore, the dimensions of the window that will maximize the area would be $W\approx 8.72$ and $L\approx 15.57$ .

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3 years ago

How to use a bar model?

riadik2000 [5.3K]

You make a bar and you take 34 and shade 18. Count the squares not shaded.

Don't take my word on this. I may be wrong.

4 0

2 years ago

What number(s) have the absolute value of 7? Why? (Must explain to receive credit)

Liula [17]

Answer:

Why is | 7 | the absolute value of the number 7?

The absolute value of a number is how far away the number is from zero. The absolute value is ALWAYS positive.

What is the absolute value of -7?

The negative version of the number is also | 7 |

Step-by-step explanation:

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3 years ago

Read 2 more answers

I need help its not 4236

Oduvanchick [21]

Answer: 4236

Step-by-step explanation: I used a calculator. If it's wrong, tell your teacher/instructor.

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2 years ago