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3 years ago

Classify the following triangle as acute, obtuse, or right.

Mathematics

1 answer:

Elenna [48]3 years ago

3 0

Answer:

It is an obtuse angle so correct

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What is the slope of the line whose equation is -3x+y=12

docker41 [41]

$3x is the answer as the opposite of -3 in front of x is 3$

6 0

3 years ago

Read 2 more answers

On a map, 3 centimeters represents 150 kilometers. If a line between two cities measures 4.5 centimeters, how many kilometers ap

SCORPION-xisa [38]

Answer: 225km

Step-by-step explanation:

3cm --- 150

1cm ---- 50

Therefore 4.5cm * 50 = 225km

7 0

3 years ago

Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Check all that apply.

DIA [1.3K]

Reta a:

$3x-4y=7 \\ -4y=-3x+7 \\ 4y=3x-7 \\ y= \frac{3}{4}x- \frac{7}{4}$

reta x:

$y=ax+b$

Retas paralelas possuem coeficientes angulares iguais ⇒ mₐ=mₓ

$y= \frac{3}{4}x+b$

(-4,-2)

$\frac{3}{4}.(-4)+b=-2 \\ -3+b=-2 \\ b=-2+3 \\ b=1$

∴ y=3/4x+1

8 0

3 years ago

Find for x<br><br> 1/5x + 1/3= 3(2/3x -2)

topjm [15]

Answer:

The value of x for the given expression is (95/27)

Step-by-step explanation:

Here, the given expression is:

$\frac{1}{5} x + \frac{1}{3} = 3(\frac{2}{3}x -2)$

Now here solving for the value of x , we get

$\frac{1}{5} x + \frac{1}{3} = 3(\frac{2}{3}x) -6\\\implies\frac{1}{5} x + \frac{1}{3} = 2x -6$

Now, taking the variable terms on 1 side, we get

$\frac{1}{5} x - 2x = -6 - \frac{1}{3} \\\implies\frac{x - 10x}{5} = -(\frac{6(3) +1}{3} )$

or, $\frac{-9x}{5} = -\frac{19}{3} \implies x = \frac{19}{3} \times\frac{5}{9} = \frac{95}{27}$

Hence, the value of x = (95/27)

6 0

4 years ago

Problem PageQuestion Working together, two pumps can drain a certain pool in hours. If it takes the older pump hours to drain th

gizmo_the_mogwai [7]

Answer:

10.5 hours.

Step-by-step explanation:

Please consider the complete question.

Working together, two pumps can drain a certain pool in 6 hours. If it takes the older pump 14 hours to drain the pool by itself, how long will it take the newer pump to drain the pool on its own?

Let t represent time taken by newer pump in hours to drain the pool on its own.

So part of pool drained by newer pump in one hour would be $\frac{1}{t}$ .

We have been given that it takes the older pump 14 hours to drain the pool by itself, so part of pool drained by older pump in one hour would be $\frac{1}{14}$ .