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Leona [35]
1 year ago
13

Which of the following is an advantage of software-defined networking (SDN)?

Computers and Technology
1 answer:
GREYUIT [131]1 year ago
3 0

The option which represents an advantage of software-defined networking (SDN) is that it determines more granular control. Thus, the correct option for this question is D.

<h3>What is software-defined networking?</h3>

Software-defined networking may be characterized as an approach to networking that effectively utilizes software-based controllers or application programming interfaces (APIs) in order to communicate with underlying hardware infrastructure and direct traffic on a network.

According to the context of this question, the most common advantages of SDN are traffic programmability, agility, and the ability to create policy-driven network supervision and implement network automation.

Therefore, more granular control is an option that represents an advantage of software-defined networking (SDN). Thus, the correct option for this question is D.

To learn more about Software-defined networking, refer to the link:

brainly.com/question/24321959

#SPJ1

You might be interested in
When you make taffy (a pliable candy), you must heat the candy mixture to 270 degrees Fahrenheit.
Sergeeva-Olga [200]

Explanation:

Here's my solution:

import java.util.Scanner; // We start by importing the Scanner, which enables us to put in values

public class Main // our class. Name doesn't really matter here.

{ // Open the brackets of the class.

   

public static void main(String[] args) { // This is our main method. It will run when we run the class.

    System.out.println("Starting Taffy Timer..."); // When we start the timer, we will print out that we do so

 Scanner re = new Scanner(System.in); // Import the scanner into the main method

 int temp; // Define the integer called temperature that the user will put in

 do { /* This is a do while loop -- it will go through the loop, and then it will check the value.

      I decided to use this because we can define temperature without checking the value first.

     What this loop is doing is taking in the temperature, and then checking if it's right. If

     it's a high enough temperature, it will tell the user that it's ready, but if not, it won't. */

     temp = re.nextInt(); // Allow the user to enter in the temperature

     if(temp >= 270) { // if it's high enough, say that it's ready

         System.out.println("Your taffy is ready for the next step!");

         

     }

     else { // if not, don't

          System.out.println("The mixture isn't ready yet.");

         

     }

 }

 while(temp < 270); // This makes sure that if it's ready for the next step, we don't have to continue

}

}

5 0
3 years ago
How should font appear in a slide presentation compared to the font in a document
saul85 [17]

Answer:

larger in a presentation, smaller on a document.

Explanation:

this makes it easier to tell which is which.

3 0
3 years ago
One of your professors has asked you to write a program to grade her midterm exams, which consist of only 20 multiple-choice que
Lorico [155]

Answer:  

Here is the program that determines the number of questions that the student answered correctly.

#include <iostream>  //to use input output functions

#include <fstream>  // to handle files

#define size 20  //size of questions is fixed to 20

using namespace std;   //to identify objects cin cout

int correctAnswers(char answers[], char correct[]);  //to count correct answers given by student

   int main(){    //start of main function

       char correct[size];         // array stores correct answers

       char answers[size];       //stores answers of students

       int result;                     //stores the correct answers result of student

       double percentage;   //stores the percentage of correct answers

       int counter;        //counts number of correct answers given by student  

       ifstream reader("CorrectAnswers.txt");  //reads the contents of CorrectAnswers.txt file

       if(!reader){  //if file cannot be read/opened

           cout<<"Cannot open the file"<<endl; //displays error message

           return 0;        }          

       counter = 0;    //sets counter to 0 initially

       while( (reader>>correct[counter++]) && counter < size  );    //reads each answer from CorrectAnswers.txt  and stores it in char array correct[] at each iteration of while loop

       reader.close();  //closes the file

       reader.open("StudentAnswers.txt");    //opens StudentAnswers.txt file  

       if(!reader){   //if file could not be opened

           cout<<"Cannot open file"<<endl;   //displays this error message

           return 0;          }          

       counter = 0;    //sets counter to 0

       while( (reader>>answers[counter++]) && counter < size );   //reads each answer from StudentAnswers.txt  and stores it in char array answers[] at each iteration of while loop    

       result = correctAnswers(answers,correct);  //calls correctAnswers method to compute the correct answers given by student and stores the result of correct answers in result variable

       percentage = 100.0*result/size;   //computes percentage of correct answers of student    

       cout<<"The total number of questions answered correctly: "<<result<<endl;     //displays total no of qs answered correctly

       cout<<"The percentage of questions answered correctly: "<<percentage<<" %"<<endl;  //displays computed percentage

       if( percentage >= 75 ){  //if percentage of correctly answered questions is 75% or greater

           cout<<"Student has passed the exam!"<<endl;   } //displays that the student passed the exam

      else { //if percentage of correctly answered questions is below 75%

           cout<<"Student has failed the exam!"<<endl;         }  //displays that the student failed the exam

       return 0;     }  

   int correctAnswers(char answers[], char correct[]){   //method to compute the number of correct answers  

       int countCorrect = 0;   //stores the count of correct answers

       for(int i=0; i<size; i++){  //iterates 20 times to match answers from both the files of 20 questions

           if( answers[i] == correct[i] ){  // if the student answer in StudentAnswers.txt file matches with the correct answer given in CorrectAnswers.txt file

               countCorrect++;              }         }     //adds 1 to the countCorrect every time the student answer matches with the correct answer

       return countCorrect;     }  //returns the number of questions that the student answered correctly

Explanation:

The program is well explained in the comments mentioned with each line of code.

Here are the two files that can be used to check the working of the above program. You can create your own text files too.

     CorrectAnswers.txt :

A

A

B

D

C

C

A

C

D

D

A

B

A

B

B

C

A

C

C

B

StudentAnswers.txt

A

C

B

D

C

C

B

C

D

C

D

B

A

B

B

C

A

C

C

B      

Also if the number of wrong answers are to be displayed then add this method to the above code:

void wrongAnswers(char answers[], char correct[]){  //method takes two arrays one with correct answers and the other with student answers

       for(int i=0; i<size; i++){ //iterates 20 times

           if( answers[i] != correct[i] ){ //if the answer by student does not match with correct answer

               cout<<"Question Number: "<<i+1<<endl; //the question that is answered incorrectly

               cout<<"Correct answer is: "<<correct[i]<<endl;  //displays the correct answer

               cout<<"Student answer is: "<<answers[i]<<endl;    }    }    } //displays the answer that student gave

Now call this method in main() as:

if(result < size){  //if result is less than size i.e. 20

           cout<<"The questions answered incorrectly"<<endl;  //number of questions that are answered incorrectly

           wrongAnswers(answers,correct);  //calls method to compute the wrongly answered questions

       }else{  //if result is not less than size

           cout<<"No incorrect answers."<<endl;       }    //no questions incorrectly answered      

       cout<<"Number of missed questions: "<<size-result<<endl; //displays the number of missed questions

The screenshot of the output is attached.

8 0
3 years ago
What are the two compatibility issues that may arise between computer systems while transferring presentations? different video
Mamont248 [21]

Different video files and operating system versions can cause compatibility issues to arise between computer systems.

Since, file formats and operating systems may not be compatible with each other. For example, earlier versions of Windows may not be able to play certain types of video files due to the codecs used to encode them.

<h3>Importance of compatibility between operating system computer systems</h3>

Compatibility between operating systems is important because it allows different computer systems to interact and share resources. This includes sharing of programs, files, and data.

Compatibility also allows users to access applications and services on different platforms. It also enables efficient use of hardware and software resources, as well as efficient use of resources in a network. Compatibility also ensures that computer systems can communicate with each other and can access the same resources. Without compatibility, it would be difficult for computer systems to interact with each other.

What are two compatibility issues that may arise between computer systems while transferring presentations? (Fill in the blank).

Different video files and _____ can cause compatibility issues to arise between computer systems.

Learn more about Compatibility between operating systems:

brainly.com/question/24760752

#SPJ4

4 0
1 year ago
Can you prove that the bleu areas are the same please?
Nookie1986 [14]

\huge\color{darkred}{ \tt{NO!!}}

8 0
2 years ago
Read 2 more answers
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