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Given information
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First showing : 1.30pm
Second showing : 4.15 pm
Inbetween : 1/2 hour break
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Find the time the first showing ends
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1/2 hours before 4.15pm
⇒ 30 mins before 4.15pm
⇒ 3.45pm
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Calculate the duration of the firs show
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1.30pm to 3.30pm = 2 hours
3.30pm to 3.45pm = 15 mins
Total duration = 2 hours 15 mins
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Answer: 2 hours 15 mins
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Answer:
2) ∠SDH and ∠SDT are right angles because SD ⊥ HT.
3)
as it is given in the question.
4)
is the reflexive property.
5) ΔSHD ≅ ΔSTD by RHS congruency.
Step-by-step explanation:
Given in the question:
![\bar{SH}\cong \bar{ST}\\\bar{SD}\perp \bar{HT}](https://tex.z-dn.net/?f=%5Cbar%7BSH%7D%5Ccong%20%5Cbar%7BST%7D%5C%5C%5Cbar%7BSD%7D%5Cperp%20%5Cbar%7BHT%7D)
In ΔSHD and ΔSTD
(Given)
(SD ⊥ HT)
(Common)
Therefore,
(By RHS rule)
Reflexive property of congruency is defined as the property in which something is equal to itself. Hence, the reflexive property of these two triangles is ![\bar{SD}\cong \bar{SD}](https://tex.z-dn.net/?f=%5Cbar%7BSD%7D%5Ccong%20%5Cbar%7BSD%7D)
Firstly you forgot to attach the mathematical work along with your question. I am answering the question based on my research and knowledge and hope that it helps you. "The simplification performed in step 2 is invalid or incorrect" is the statement that <span>best applies to the sample mathematical work. The correct option among all the options given in the question is option "B".</span>
Answer:
45.7 meters.
Step-by-step explanation:
Please see the attachment.
Let h be the height of the tower.
We have been given that tower of a tower crane casts a shadow (on level ground) of 32 m when the sun is 55° above the horizon.
We can see from our attachment that height of the tower will be opposite side to 55 degree angle and shadow of the tower is adjacent side to angle.
Since tangent relates the opposite and adjacent sides of a right triangle, so we will use tangent to find the height of the tower.
![\text{Tan}=\frac{\text{Opposite}}{\text{Adjacent}}](https://tex.z-dn.net/?f=%5Ctext%7BTan%7D%3D%5Cfrac%7B%5Ctext%7BOpposite%7D%7D%7B%5Ctext%7BAdjacent%7D%7D)
Upon substituting our given values we will get,
![\text{Tan }(55^o)=\frac{h}{32}](https://tex.z-dn.net/?f=%5Ctext%7BTan%20%7D%2855%5Eo%29%3D%5Cfrac%7Bh%7D%7B32%7D)
![1.428148006742=\frac{h}{32}](https://tex.z-dn.net/?f=1.428148006742%3D%5Cfrac%7Bh%7D%7B32%7D)
![32*1.428148006742=32*\frac{h}{32}](https://tex.z-dn.net/?f=32%2A1.428148006742%3D32%2A%5Cfrac%7Bh%7D%7B32%7D)
![h=45.7007\approx 45.7](https://tex.z-dn.net/?f=h%3D45.7007%5Capprox%2045.7)
Therefore, height of the tower is 45.7 meters.
Answer:
yes
Step-by-step explanation:
2x4-5=3
8-5=3