The first line equation: y = -2/7x - 5; m1 = -7/2
The second line passes through (2,4) and is perpendicular to the first line.
Therefore,
The gradient of first line = -1/m1 = -1/(-2/7) = 7/2
Then, the equation of the second line is;
y = 7/2x+b
Substituting for the coordinates given;
4 = 7/2(2)+b
4 = 7+b
b = 4-7 = -3
Therefore, the equation of the second line is;
y = 7/2x - 3
In standard form, the equation this equation can be written as:
y(2) = 7x - 3(2)
2y = 7x - 6
7x -2y - 6 = 0 -----> standard form.
Answer:
Cotton
Step-by-step explanation:
I just took the test
Given:
The function is

To find:
The range value if the domain value is 1.75.
Solution:
Domain is the set of input values and range is the set of output values.
Here, range value if the domain value is 1.75. It means the value of function f(x) at x=1.75.
Substitute x=1.75 in the given function.



Therefore, the required range value is 4.5.
The markup is 150%
126/84= 1.5
1.5 x 100 = 150%
Proof : 1.5 x 84 =126