Answer:
Step-by-step explanation:
B
2
3
Let the distance of two consecutive stones are x, x+1.
In ΔBCD, we have
tan60
o
=
x
h
⇒x=
3
h
.....(i)
In ΔABC, we have
tan30
o
=
x+1
h
⇒
3
1
=
x+1
h
⇒
3
h
+1=
3
h ......[from equation (i)]
⇒
3
2h
=1
⇒h=
2
3
km
solution
Answer:
4x² + 4y² + 8xy
Step-by-step explanation:
( 2x + 2y ) ( 2x + 2y ) = ( 2x + 2y )²
Formula : -
( a + b )² = a² + b² + 2ab
Here,
a = 2x
b = 2y
( 2x + 2y )²
= ( 2x )² + ( 2y )² + 2 ( 2x ) ( 2y )
= 2²x² + 2²y² + 8xy
= 4x² + 4y² + 8xy
Answer:
The first five terms are;
-3,-7,11,-29,69
Step-by-step explanation:
The recursive definition of the sequence is
, 
and 
.
When n=3, we obtain;
.
.
.
.
When n=4
.
.
When n=5
.
.
Therefore the first five terms are;
-3,-7,11,-29,69
I think u do the ones in the parenthesis first bc of PEMDAS since it's both negative it become positive and u can cross out both the 2's and that leaves u with 1/7 and then u just times 1/7 with 8 and then u get 8/7
hoped this helped! :)
