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gogolik [260]
3 years ago
14

Find a value of X so that the figure is a square.

Mathematics
2 answers:
rodikova [14]3 years ago
5 0
Hello !
We know that a square has all equal sides.

That means the side 3x+39 is equal to the side 3(5x-3):
            

           3x+39 = 3(5x-3)
           3x+39 = 15x-9   | - 3x 
           3x-3x+39 = 15x-3x-9
                   39 = 12x-9  | + 9
                   39 + 9 = 12x-9+9
                   48 = 12x  | ÷ 12
                   x = 48/12 ⇔ x = 4

 


So,one side is 3*4 + 39 = 12 + 39 = 51
And the other side is 3(5*4 - 3) = 3(20-3) = 3*17 = 51



As you can see,the sides are equal.
drek231 [11]3 years ago
4 0
3(5x-3)=3x+39
15x-9=3x+39
12x=48
x=4
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Which of the following is a solution of x2 + 6x = −18? x = 3 − 3i x = −3 + 3i x = −6 + 3i x = 6 − 3i
Marina86 [1]

Step 1 ) Move all terms right side of the equation.

\displaystyle\ x^{2} + 6x = -18

\displaystyle\ x^{2} + 6x + 18 = -18 + 18

\displaystyle\ x^{2} +6x + 18 = 0

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

\displaystyle\ x^{2} +6x + 18 = 0

\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}

\displaystyle\ x = \frac{-6+\sqrt{6^{2}-4 * 18}}{2} , \displaystyle\ x = \frac{-6-\sqrt{6^{2}-4*18}}{2}

\displaystyle\ x = \frac{-6+6i}{2} ,

\displaystyle\ x = \frac{-6-6i}{2}

Step 3 ) Simplify.

\displaystyle\ x = \frac{-6+6i}{2} ,

\displaystyle\ x = \frac{-6-6i}{2}

\displaystyle\ x = -3+ 3i,

\displaystyle\ x = -3 - 3i

Since the options only provide one of the answer we found, the answer is...

\displaystyle\ x = -3 - 3i

•

•

- <em>Marlon Nunez</em>

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HELP PLEASE! I WILL GIVE BRAINLIEST
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
A man has 1 coins in his pocket, all of which are dimes and quarters. Aif the total value of his change is $2.75, how many dimes
VLD [36.1K]

Using a system of equations, it is found that there are 5 dimes and 9 quarters in his pocket.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

  • Variable x: number of dimes in his pocket.
  • Variable y: number of quarters in his pocket.

He has a total of 14 coins, hence:

x + y = 14 -> y = 14 - x.

They are worth $2.75, hence, considering the value of each coin(dimes $0.1 and quarters $0.25), we have that:

0.1x + 0.25y = 2.75

Since y = 14 - x:

0.1x + 0.25(14 - x) = 2.75

x = (0.25*14 - 2.75)/0.15.

x = 5.

y = 14 - x = 14 - 5 = 9.

There are 5 dimes and 9 quarters in his pocket.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

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