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3 years ago

Given the graph of g (x) below determine g (1)

Mathematics

1 answer:

yawa3891 [41]3 years ago

8 0

Answer:

-2

Step-by-step explanation:

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How many 1/16 pound servings are there in a bag of almonds that weighs 3/4 pounds

gavmur [86]

Answer:

12 servings.

Step-by-step explanation:

That would be 3/4 divided by 1/16.

3/4 / 1/16 Invert and multiply:

= 3/4 * 16/1

= 48 / 4

= 12.

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2 years ago

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vodka [1.7K]

Answer:

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Step-by-step explanation:

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3 years ago

Plss help asap :) <br><br><br> (if your reading this I hope you have a great day!)

Alika [10]

Neither.

Parallel lines have the same slope.
Perpendicular lines have negative reciprocal slopes.

Rewriting the 2nd equation to solve for y,
You get:

Y=1/5x + 1/2

The first equation slope is negative, and the second is positive. However, the second slope is 1/5, and not 5/1 - which would be the negative reciprocal of (-1/5)from the first equation.

Hope that helps!

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3 years ago

A parabola has the equation f(x) = 2(x − 3)2 − 4. Complete:

RUDIKE [14]

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

f(x) = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

f(x) = 2(x - 3)² - 4 ← is in vertex form

with (h, k) = (3, - 4), thus

1 the vertex is (3, - 4 )

Consider the value of a

• If a > 0 then graph opens up and is a minimum

• If a < 0 then graph opens down and is a maximum

2 Here a = 2 thus the graph opens up

The max/ min value of the function is the y- coordinate of the vertex, thus

3 The function has a minimum value of - 4

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3 years ago

Find what the question asks. 200 points. Will mark brainleist

kotegsom [21]

Note:
The area of a circle with radius r is πr².
An entire circle has a central angle of 360°.

For the sector with radius = (3+4) = 7cm and a central angle of 120°, the area is
$A_{1}= \frac{120}{360}*(49 \pi ) = \frac{49}{3} \pi \, cm^{2}$

For the sector with radius = 3 cm and a central angle of 120°. the area is
$A_{2}= \frac{120}{360} *(9 \pi ) = 3 \pi \, cm^{2}$

The area of the shaded sector (see the figure) is
$A=A_{1}-A_{2} = ( \frac{49}{3} -3) \pi = \frac{40}{3} \pi \, cm^{2}$

Answer: $\frac{40}{3} \pi \, cm^{2}$

6 0

3 years ago

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