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vfiekz [6]
3 years ago
6

Given the graph of g (x) below determine g (1)

Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0

Answer:

-2

Step-by-step explanation:

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The sides of a rhombus are equal length, so you have

... 5x + 20 = 6x + 10

... 10 = x . . . . . . . . subtract 5x+10

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... 5·10 +10 = 70

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Brittany was tracking the increasing temperature in the morning. At 8 a.m., it was 68 degrees Fahrenheit. At 10 a.m., it was 74
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Write the equation of the line parallel to y = 2x + 1 that passes through the point (6, 2).
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y=2x-10

Step-by-step explanation:

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Medical scientists study the effect of acute infection on tissue-specific immunity. In a collection of experiments under the sam
Serjik [45]

Answer:

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

In a collection of experiments under the same conditions, 44 of 75 mice test positive for lymphadenopathy. This means that n = 75 and \pi = \frac{44}{75} = 0.586.

Compute a 95% confidence interval for the true proportion of mice that will test positive under similar conditions.

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 - 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.5291

The upper limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.586 + 1.96\sqrt{\frac{0.586*0.414}{75}} = 0.6429

The 95% confidence interval  for the true proportion of mice that will test positive under similar conditions is (0.5291, 0.6429).

7 0
3 years ago
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