The answer:
the full question is as follow:
if A+B-C=3pi, then find sinA+sinB-sinC
first, the main formula of sine and cosine are:
sinC = 2sin(C/2)cos(C/2)
sinA +sinB = 2sin[(A+B)/2]cos[(A-B)/2]
therefore:
sinA+sinB-sinC = 2sin[(A+B)/2]cos[(A-B)/2] - 2sin(C/2)cos(C/2)
sin[(A+B)/2] = cos(C/2)
2sin(C/2)cos(C/2) = cos[(A+B)/2
and
A+B-C=3 pi implies A+B =3 pi + C, so
cos[(A+B)/2] = cos [3 pi/2 + C/2]
and with the equivalence cos (3Pi/2 + X) = sinX
sinA+sinB-sinC = cos(C/2)+ sin(C/2)
I will add the length and convert it to yards and then subtract it from 4/6 yards.
Hello,
Answer B: false
the parallelogram is a rectangle
Given:
There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.
To find:
Part a: Define the variables.
Part b: Set up an equations that can be solved to find the integers.
Part c: Find the integers.
Solution:
Part a:
Let x be the first odd integers. Then next consecutive odd integer is
, because the difference between two consecutive odd integers is 2.
Part b:
Square of first odd integers = 
Three times of second odd integers = 
It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

Part c:
The equation is:

It can be written as:



Splitting the middle term, we get




-6 is not an odd integer, so
and the first odd integer is 3.
Second odd integer = 
= 
= 
Therefore, the two consecutive odd integers are 3 and 5.
Answer:
speed = distance ÷ time
6÷2 = 3
his speed is 3 miles per hour
he can cover 3 more miles....