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1 year ago

13

Eric orders 3 large cheese pizzas. There is a $2 delivery fee for each pizza. He pays a total of $42. Which equation can be used

to find the price, r, of each pizza?

1 answer:

Llana [10]1 year ago

4 0

we have that he paid 4 dollars due the delivery. So each pizza costs

$\frac{38}{2}=19$

so the equation to find the price r is

$r=\frac{42-4}{2}$

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Will mark brainliest.

Verizon [17]

Answer:

18 x and 6 y

Step-by-step explanation:

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4 0

3 years ago

Read 2 more answers

The expression 8x2 − 144x 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represent

Rzqust [24]

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Given expression 8x² − 144x + 864 is used to approximate a small town's population in thousands from 1998 to 2018, where x represents the number of years since 1998.

<h3>What is a quadratic equation?</h3>

A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.

Given expression is 8x² − 144x + 864

Let y = 8x² − 144x + 864

also, y - 864 = 8x² - 144x

by Extracting common factor 8 on the right side

y - 864 = 8(x² - 18x)

Add (18/2)² on both sides, we get

y - 864 + 8(18/2)² = 8 (x² - 18x + 81²)

y - 864 + 648 = 8 (x² - 8x + 9)

on simplification

y - 216 = 8 (x - 9)²

y = 8(x - 9)² + 216

therefore, y = 8 (x - 9)² + 216

The expression that is most useful for finding the year where the population was at a minimum would be 8(x − 9)² + 216.

Learn more about a quadratic equation here:

brainly.com/question/2263981

8 0

2 years ago

3. Robin drove 80 miles in 1.6 hours.

Naya [18.7K]

Answer:

c

Step-by-step explanation:

hope this help!

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3 years ago

Please help! functions operations. explain please

Lina20 [59]

Answer:

$f^{-1}(x)=x^2-3$

Step-by-step explanation:

Given $f(x)=\sqrt{x+3}$

Let $y=\sqrt{x+3}$

Interchange x and y

$x=\sqrt{y+3}$

Solve for y, by first squaring both sides

$x^2=y+3$

$x^2-3=y$

Hence

$f^{-1}(x)=x^2-3$

The last choice is correct

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cbegin%7Bequation%7D%5Ctext%20%7B%20Question%3A%20If%20%7D%20%5Cln%20%28x%2By%29%3D4%20%5Cti

Art [367]

I think you meant to say

$\ln(x+y) = 4xy$

and not "4 times y" on the right side (which would lead to a complex value for y when x = 0). Note that when x = 0, the equation reduces to ln(y) = 0, so that y = 1.

Implicitly differentiating both sides with respect to x, taking y = y(x), and solving for dy/dx gives

$\dfrac{1+\frac{dy}{dx}}{x+y} = 4y + 4x\dfrac{dy}{dx}$

$\implies \dfrac{dy}{dx} = \dfrac{4xy+4y^2-1}{1-4x^2-4xy}$

Note that when x = 0 and y = 1, we have dy/dx = 3.

Differentiate both sides again with respect to x :

$\dfrac{d^2y}{dx^2} = \dfrac{(1-4x^2-4xy)\left(4y+4x\frac{dy}{dx}+8y\frac{dy}{dx}\right)-(4xy+4y^2-1)\left(-8x-4y-4x\frac{dy}{dx}\right)}{(1-4x^2-4xy)^2}$

No need to simplify; just plug in x = 0, y = 1, and dy/dx = 3 to get

$\dfrac{d^2y}{dx^2} \bigg|_{x=0} = \boxed{40}$

8 0

2 years ago