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navik [9.2K]
3 years ago
5

The foreman of a bottling plant has observed that the amount of soda in each 32-ounce bottle is actually a normally distributed

random variable, with a mean of 32.2 ounces and a standard deviation of 0.3 ounce.
If a customer buys one bottle, what is the probability that the bottle will contain more than 32 ounces?

If a customer buys a cartoon of four bottles. What is the probability that the mean amount of the four bottles will be greater than 32 ounces?
Mathematics
1 answer:
aksik [14]3 years ago
6 0

Answer:

Step-by-step explanation:

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A radio station claims that the amount of advertising per hour of broadcast time has an average of 13 minutes and a standard dev
zimovet [89]

Answer:

Z = 3.33

Step-by-step explanation:

Z-score:

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 13, \sigma = 1.2

You listen to the radio station for 1​ hour, at a randomly selected​ time, and carefully observe that the amount of advertising time is equal to 17 minutes. Calculate the​ z-score for this amount of advertising time.

We have to find Z when X = 17. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 13}{1.2}

Z = 3.33

5 0
3 years ago
The temperature of a hot steak starts at 140f and decreases at 5f per minute what will the temperature of this steak after a cer
irina1246 [14]

Answer:

T(m) = (140 - 5m)

Step-by-step explanation:

Given that :

Initial temperature, a = 140 F

Rate of decrease = 5 F per minute

Given a certain Number of minutes, m

Temperature, T after m minutes ;

Using the formula :

Final temperature = Initial temperature - 5*number of minutes)

T(m) = (140 - 5m)

Given that ; m = 10

T(10) = 140 - 5(10)

T(10) = 140 - 50

T(10) = 90 F

7 0
3 years ago
For g(x)=x^2-x find g(x) when x=-2
torisob [31]

Answer:

g(x) = 6

Step-by-step explanation:

Begin with substuting the x variable with -2, we do this because the question has listed the value of x already.

Using the value of x, -2 we determine g(x).

g(x) = -2^2 + 2

Above is what the equation would look as, after you input the value of -2.

Using pemdas, (parantheses, exponents, multiplication, division, addition, subtraction) solve the equation.

-2^2 = 4

Think of it as -2 * -2, which is why -2^2 is 4.

Add 4 +2.

4 + 2 = 6.

Therefore, the value of g(x) = 6

6 0
3 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
2 years ago
Help I need to know I only have 15 min <br> What does x equal in x/2=-5
SSSSS [86.1K]

Answer:

x= -10

Step-by-step explanation:

Brainliest please? :)

3 0
3 years ago
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