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saveliy_v [14]
4 years ago
9

In PE class Flynt is choosing 2 members for his dodgeball team. If he can choose 2 individuals from a group of 6 classmates, how

many possible combinations exist? A) 10 B) 12 C) 15 D) 22
Mathematics
2 answers:
Elza [17]4 years ago
8 0

Answer:

15

Step-by-step explanation:

Tatiana [17]4 years ago
7 0

Answer:

C) 15

Step-by-step explanation:

Here we have to use the combination to find the number of possible combinations.

Total number of classmates (n) = 6

We are selecting 2 individuals. So r = 2.

The combination formula nCr = \frac{n!}{r!(n-r)!}

Plug in n = 6 and r =2, in the above formula, we get

= \frac{6!}{2!(6-2)!}

= \frac{6!}{2!4!}

Simplifying the above factorial, we get

= 15

So the answer is C) 15

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Answer:

C = 36 pi or approximately 113.04

Step-by-step explanation:

The circumference of a circle is given by

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C = 2*pi*18

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We can approximate pi by 3.14

C = 36*3.14

C =113.04

3 0
3 years ago
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Afina-wow [57]

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4 0
3 years ago
Read 2 more answers
Can someone help me find AC​
Kryger [21]

Answer:

1.4

Step-by-step explanation:

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4 0
3 years ago
How do you find the solution
aleksandr82 [10.1K]
Given that there were 30 bacteria present originally.
a=30
Also given that the number doubles every one hour.
After one hour the count =2×30=60
Since the count doubles every hour it forms a G.P. with r=2
a,ar,ar2........
The count at the end of 2nd hour=ar^2=30×2^2=120
The count at the end of 4th hour=ar^4=30×2^4=480
The count at the end of 8th hour=ar^8n=30×2^8=7680
etc.
The count at the end of n^th hour=ar^n=30×2^n

Also, the equation y=30*(2)^8/1 give the same result y= 7680


4 0
3 years ago
Simplify 25(14–27)+25÷16. a 28/5 b16/5 c 31/5 d 36/5
serg [7]

Answer:

-323.4375

Step-by-step explanation:

8 0
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