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saveliy_v [14]
3 years ago
9

In PE class Flynt is choosing 2 members for his dodgeball team. If he can choose 2 individuals from a group of 6 classmates, how

many possible combinations exist? A) 10 B) 12 C) 15 D) 22
Mathematics
2 answers:
Elza [17]3 years ago
8 0

Answer:

15

Step-by-step explanation:

Tatiana [17]3 years ago
7 0

Answer:

C) 15

Step-by-step explanation:

Here we have to use the combination to find the number of possible combinations.

Total number of classmates (n) = 6

We are selecting 2 individuals. So r = 2.

The combination formula nCr = \frac{n!}{r!(n-r)!}

Plug in n = 6 and r =2, in the above formula, we get

= \frac{6!}{2!(6-2)!}

= \frac{6!}{2!4!}

Simplifying the above factorial, we get

= 15

So the answer is C) 15

You might be interested in
your gym membership cost $33 per month after an initial membership fee. you paid a total of $228 after 6 months. writer an equat
grin007 [14]

Answer:

what i did was multiply 33*6 and got 198 and then 228-198 to find out that the initial fee was 30 dollars. then multiply 33*9+30 to get a  9-month total cost of $327

Step-by-step explanation:

cost = $33 per month + fee  

1.  c(m) = 33m + f

 33(6) + f = 228

198 + f = 228

f = $30 membership fee  

c(m) = 33m + 30

 2.  at 9 months:  33(9) + 30 = $327

hopefully this helps :)

have a nice day !!

7 0
2 years ago
Solve: 7/9 = x/3<br> 0.33<br> 2.33<br> 23.3<br> 33
Novosadov [1.4K]

Step-by-step explanation:

\frac{7}{9}  =  \frac{x}{3}  \\  \\ x =  \frac{7 \times 3}{9}  \\  \\ x =  \frac{7}{3}  \\  \\  \huge \red{ \boxed{x = 2. 33}}

4 0
3 years ago
Read 2 more answers
Morgan obtains a loan for $5,700. How much money (in dollars) does she actually receive assuming a loan fee of 0.95%? (Enter an
sergeinik [125]

Answer: $5645.85

Step-by-step explanation: a loan fee of $54.15 was deducted

4 0
3 years ago
Read 2 more answers
The functions f and g are defined as follows.
monitta

Answer:

f(-3)= -48 g(6)= -8

Step-by-step explanation:

the the numbers into the corresponding functions and simplfy following the order of operations which would look like this:

f(-3)=2(-3)^3 + 6

=2(-27)+6

=-54+6

f(-3)=-48

and

g(6)= -2(6)+4

= -12+4

g(6)= -8

Hope this helps! :)

7 0
2 years ago
Given is a finite set of spherical planets, all of the same radius and no two intersecting. On the surface of each planet consid
wariber [46]

Answer:

Step-by-step explanation:

To answer this question, First, we define a direction in space, which defines

the North Pole of each planet.

We also assume that the direction is not at 90° perpendicular to the axis of any two planet.

Assume we now define an order on the set of planet by saying that planet A ≥ B, when removing all the other planet from space, the north pole B, is visible from A.

If we refer to the direction of the planet in the diagram, we discover that,

1, A ≥ A

2, If A ≥ B and B≥ A,

Then A = B

3, If A ≥ B, and B ≥ C , then A ≥ C

4, Either A ≥ B or B ≥ A

It should also be noted that the array of order above has a unique maximal element  (M). This is the only  planet whose North Pole is not visible from another.

If we now consider a sphere of the same radius as the planets. Remove

from it all North Poles defined by directions that are perpendicular

to the axis of two of the planets. This is a set of area zero.

For every other point on this sphere, there exists a direction in

space that makes it the North Pole, and for that direction, there

exists a unique North Pole on one of the planets which is not visible

from the others. Hence the total area of invisible points is equal

to the area of this sphere, which in turn is the area of one of the  planets.

5 0
2 years ago
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