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Answer:
22.86% probability that the persons IQ is between 110 and 130
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If one person is randomly selected what is the probability that the persons IQ is between 110 and 130
This is the pvalue of Z when X = 130 subtracted by the pvalue of Z when X = 110.
X = 130
has a pvalue of 0.9772
X = 110
has a pvalue of 0.7486
0.9772 - 0.7486 = 0.2286
22.86% probability that the persons IQ is between 110 and 130
Answer: 0.475 cups of broth per serving.
Explanation:
1) Ratio given:
i) To facilitate the operations, transform the mixed number 4 3/4 cups into improper fraction:
4 + 3/4 = [16 + 3] / 4 = 19 / 4
ii) ratio broth: servings
2) Proportion with the unknown number of cups of broth per serving:
3) Solve for the unknown:
x = [19 / 4] cups × 1 serving / 10 servings = 19 / 40 cups = 0.475 cups
Explanation:
1) Ratio given:
i) To facilitate the operations, transform the mixed number 4 3/4 cups into improper fraction:
4 + 3/4 = [16 + 3] / 4 = 19 / 4
ii) ratio broth: servings
2) Proportion with the unknown number of cups of broth per serving:
3) Solve for the unknown:
x = [19 / 4] cups × 1 serving / 10 servings = 19 / 40 cups = 0.475 cups