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Lana71 [14]
3 years ago
10

The length of a dance floor to be replaced is 1 foot shorter than twice than width. You measured the width to be 12.25 feet. Wha

t is the area and what is the most accurate area you can report?
Mathematics
2 answers:
telo118 [61]3 years ago
7 0
12.25x2=24.50 (width x2)
24.50-1=23.50 (length)


Area= LxW
        =23.50x12.25
        =287.88 feet

Illusion [34]3 years ago
5 0

Answer:

287.875 square feet.

Step-by-step explanation:

Let x be the width ( in feet ) of the dance floor,

∵ the length of a dance floor to be replaced is 1 foot shorter than twice than width.

So, the length of the dance floor = 2x - 1

According to the question,

x = 12.25 ft,

⇒ 2x - 1 = 2(12.25) -1 = 23.5 ft,

Thus, the area of the floor = length × width

= 23.5 × 12.25

= 287.875 square feet.

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