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AlekseyPX
3 years ago
10

A cylindrical roller 2.5 m in length, 1.5 m in radius when rolled on a road was found to cover the area of 16500 m2 . How many r

evolutions does it make ?
Mathematics
1 answer:
eduard3 years ago
8 0

Answer:

701 revolutions

Step-by-step explanation:

Given: Length= 2.5 m

            Radius= 1.5 m

            Area covered by roller= 16500 m²

Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.

Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.

Formula; Lateral surface area of cylinder= 2\pi rh

Considering, π= 3.14

⇒ lateral surface area of cylinder= 2\times 3.14\times 1.5\times 2.5

⇒ lateral surface area of cylinder= 23.55 \ m^{2}

∴ Area covered by cylindrical roller in one revolution is 23.55 m²

Next finding total number of revolution to cover 16500 m² area.

Total number of revolution= \frac{16500}{23.55} = 700.6369 \approx 701

Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.

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A system is inconsistent when there are no solutions between the two equations. Graphically, the lines will be parallel (they never meet!) and the slopes will be the same. But the y-intercepts will be different.

Let's look at the four equations, with each solved as needed, into y = mx + b form.

A: 2x + y = 5

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Compared to y = 2x + 5, the slopes are different, so this system won't be inconsistent. Not a good choice.

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C: 2x - 4y = 10

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y = 2x - 5

Compared to y = 2x + 5 we have the same slopes and different y intercepts.  The lines will be parallel and the system is inconsistent.


Thus, D is the best choice.

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