Step-by-step explanation:
This is a probability related problem.
Probability is the likelihood of an event to occur;
Pr = 
The sample space here is from 1 to 25 which is 25
A.
Pr of a card marked 8; we have just 1 possible outcome;
Pr(8) =
B.
Pr of drawing a card that is a multiple of 5;
Multiples of 5 = 5, 10, 15 and 25
Pr (multiples of 5) =
C.
Pr of drawing a card with odd numbers:
Number of odd numbers between 1 and 25 = 13
Pr(odd numbers) =
D.
Pr of drawing a number with square number on it;
Square numbers between 1 and 25 = 1, 4, 9, 16 and 25
Pr(square numbers) =
= 
Answer:
Rosaria purchased 50 bracelets and 70 necklaces
Step-by-step explanation:
Let the number of bracelets be b and the number of necklaces be n
b + n = 120 •••••(i)
Secondly;
10b + 11n = 1270 ••••(ii)
Total cost of b bracelets at 10 per 1 is 10b
Total cost of n bracelets at 11 per 1 is 11n
Adding both gives 1270
From i, b = 120-n
Substitute this into ii
10(120-n) + 11n = 1270
1200 - 10n + 11n = 1270
n = 1270-1200
n = 70
b = 120-n
b = 120-70
b = 50
(x, y) --> (x + 5, y - 1)
A(3, -1) --> A'(3 + 5, -1 - 1) --> A'(8, -2)
B(6, 1) --> B'(6 + 5, 1 -1) --> B'(11, 0)
C(2, 4) --> C'(2 + 5, 4 - 1) --> C'(7, 3)
D(-1, 3) --> D'(-1 + 5, 3 - 1) --> D'(4, 2)