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Ratling [72]
3 years ago
5

Drake wants to save $750 so that he can take a class on computer analysis for cars. The class is being held on various dates ove

r the next several months. Drake is planning to take the class 6 weeks from now, so he plans to save $125 each week.
Unfortunately, Drake had to take out a little money from his savings in the 3rd week. After 4 weeks, Drake has $470. He knows that he must adjust his plan in order to meet his goal. Drake came up with the following options:

Option A: Stay with saving the original amount each week but take the class a week later than originally planned.

Option B: Increase the amount of money he saves each week by $15 from his original plan.
Mathematics
2 answers:
LenaWriter [7]3 years ago
7 0

Answer:

the correct answer is C both options will work in this scenario.

Step-by-step explanation:

allochka39001 [22]3 years ago
6 0
<span>Drake can meet his $750 planned savings goal with either concept. After 4 weeks, he was $30 less than where he planned to be ($450 instead of $480). If he simply added $250 after two more weeks, he would be at $720 instead of $750, and would have to wait one more week to take the class. Conversely, if he added $15 to the next two weeks' savings, he would recoup the $30 he pulled out of the savings in those two weeks and would be back on the path to being able to take the course at the end of the 6-week period as originally planned.</span>
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Answer:

162.12385 cubic inches

Step-by-step explanation:

Assuming finding the area and circumference of the shaded area.

Triangle with 3 sides and 90 degrees on one side, we can use the Pythagorean Theorem to solve for the missing side.

Pythag. Theorem says

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//^2 means squared, or the number multiplied by itself

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Take the square root of both sides to get rid of (^2) from the right side of the equation.

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So the longest side is 34 inches.

Coincidentally, this is the diameter of the Half Circle.

The radius = (diameter/2) = 34/2 = 16 inches

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Circumference of a Circle formula:

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Area of shaded part is equal to

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