I need help with Question C

In Oakland County the fine for speeding is $15 for each mile per hour over the speed limit. Jim was fined $165 for speeding in a

shtirl [24]

Answer:

36 mph

Step-by-step explanation:

First, we have to find the unit rate of the money.

Since it's 15 dollars for each mile over the speed limit, divide 15 by 165.

The answer is 11, which means he was going 11 mph over the speed limit.

Add 11 to 25, and you get 36

7 0

3 years ago

A 9 3/5 inch long pipe is cut into eight equal length pieces. How long is each piece?

Alenkinab [10]

Answer:

1.2

Step-by-step explanation:

9 3/5 divided by 8

3 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

3 years ago

Nivyana and Ana are selling their apparel to earn money for a cruise. Knitted scarves are $50 each in Mittens are $25 per pair.

Katarina [22]

Answer:

The number of knitted scarves is 10

The number of knitted mitten is 20

Step-by-step explanation:

Given as :

The cost of each knitted scarves = $50

The cost of pairs of mittens = $25

Total number of scarves and mitten bought = 30

The total money invested to pay for items = $1000

Let The number of knitted scarves = k

Let The number of mitten = m

<u>Now, According to question</u>

The total money invested to pay for items = cost of each knitted scarves × number of knitted scarves + cost of pairs of mittens × number of mitten

i.e $1000 = $50 × k + $25 × m

Or, 40 = 2 k + m

i.e 2 k + m = 40 ........A

And

Total number of scarves and mitten bought = number of knitted scarves + number of mitten

i.e k + m = 30 ...........B

Now, solving eq A and eq B

So, (2 k + m ) - ( k + m ) = 40 - 30

Or, (2 k - k) + ( m - m) = 10

Or, k + 0 = 10

∴ k = 10

So, The number of knitted scarves = k = 10

Put the value of k into eq B

∵ k + m = 30

So, m = 30 - k

or, m = 30 - 10

∴ m = 20

The number of knitted mitten = m = 20

Hence, The number of knitted scarves is 10 and The number of knitted mitten is 20 . Answer

7 0

3 years ago

-6 < 2t - 5 < 3<br> Solve for T

natulia [17]

Answer:

I think it's 7

Step-by-step explanation:

-6 < 2T (-5+5) < 3+5

-6 < 2T < 8

+6 < 2T < 8 + 6

0 < 2T < 14

0 < ÷ 2 < ÷ 2

0 < T < 7

-0 < T < -0

T = 7

4 0

3 years ago