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Doss [256]
1 year ago
6

Mohal bought 20 chicken wings for $50.00. If Mohal spent $30.00, how many chicken wings did he buy

Mathematics
1 answer:
ELEN [110]1 year ago
7 0

The number of chicken wings that Mohal can buy is 12.

<h3>How to calculate the cost?</h3>

It should be noted that Mohal bought 20 chicken wings for $50.00. The cost of each wing will be:

= Total amount / Number of chicken wings

= $50 / 20

= $2.50

When he spent $30.00, the number of wings will be:

= Amount / Cost per wing

= $30 / $2.50

= 12

There will be 12 chicken wings. This illustrates the proportion.

Learn more about cost on:

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Can someone please explain how the answer to this is, "19 and 3", "1 and 12"
Makovka662 [10]

Using the image given, the angles that are Alternate Exterior Angles are: 1, 2, 3, 4,13,14, 18, 19.

<h3>What are Alternate Exterior Angles?</h3>

These are known to be the Alternate exterior angles that are regarded as the pair of angles found on the outer side of the two parallel lines but they are seen on the opposite side of the transversal.

Note that in the image given, there are two parallel lines and two transversal lines.

Note also that to get the Alternate exterior angles, it has to be the angles seen on the seen on the opposite side of the transversal that has crossed the parallels lines and from the image given, only angle 1, 2, 3, 4,13,14, 18, 19 fit into the description.

Therefore, Using the image given, the angles that are Alternate Exterior Angles are: 1, 2, 3, 4,13,14, 18 19.

Learn more about Alternate Exterior Angles from

brainly.com/question/2398628

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5 0
2 years ago
40 pounds of sugar are repackaged of 1/16 pounds each. how many packet of sugar are there?
jarptica [38.1K]
We know to each pound of such, there is 16 packets produced per?

So, 16 x 40 = 640.
8 0
3 years ago
A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed
KiRa [710]

Answer:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     13                      9               33

Some relief               32                   28                     27              87

Total relief                7                       9                      14               30

Total                         50                    50                    50              150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*33}{150}=11

E_{2} =\frac{50*33}{150}=11

E_{3} =\frac{50*33}{150}=11

E_{4} =\frac{50*87}{150}=29

E_{5} =\frac{50*87}{150}=29

E_{6} =\frac{50*87}{150}=29

E_{7} =\frac{50*30}{150}=10

E_{8} =\frac{50*30}{150}=10

E_{9} =\frac{50*30}{150}=10

And the expected values are given by:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     11                       11               33

Some relief               29                   29                     29              87

Total relief                10                     10                     10               30

Total                         50                    50                    50              150

And now we can calculate the statistic:

\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0
3 years ago
(x+3)^2+5=-28
Sidana [21]

Answer:

Description

Step-by-step explanation:

a. 2 solutions

b. 2 imaginary solutions

c. If the discriminant is positive, then it will have 2 real solutions as the square root of a positive number always equals a positive number. If the discriminant is negative, the quadratic equation will have 2 imaginary solutions, as the square root of a negative number is always imaginary. If the discriminant equals 0, it will have only 1 real solution.

3 0
3 years ago
Maria solved the equation below and got x = –4. Which of the following choices verifies that her solution is correct? 5x + 22 =
VladimirAG [237]
5(-4)+22 = (-4)+6
-20+22 = -4+6
2 = 2
Maria is correct, since both sides equally match.
3 0
3 years ago
Read 2 more answers
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