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aksik [14]
2 years ago
6

What is the factor of this problem? ~plz help cannot get this wrong !

Mathematics
1 answer:
Aleonysh [2.5K]2 years ago
3 0

Answer:

it should be 3x^2 +2

Step-by-step explanation:

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HELP!!! How do you do a diophantine equation? Plz help as soon as possible.
Annette [7]

Answer and Step-by-step explanation:

A Diophantine equation is simply an equation that relates whole numbers.

There are various types of Diophantine equations, but probably the most basic is the linear version: ax + by = c.

Different methods also abound for solving these types of equations:

- Coordinate geometry

- Modular arithmetic

- Induction

Hope this helps!

4 0
3 years ago
Read 2 more answers
the length of rectangle exceeds its breadth by 4 cm if the length and breadth is increased by 3 cm the area of the new rectangle
gizmo_the_mogwai [7]

Answer:

The length and breadth are 14 cm and 10 cm

3 0
2 years ago
PLEASE HELP I HAVE LIMITED TIME!!
MakcuM [25]

Answer:

N: n = 5 sides

side length: a = 23.2 m

inradius: r = 15.966 m

circumradius: R = 19.7351 m

Area: A = 926.03 m2

perimeter: P = 116 m

interior angle: x = 108 °

exterior angle:  y = 72 °

Description:

We use the calculations on the shape 16 and 23.2. Side length is 23.2. Pi is 16. calculate the numbers and all the answers are added above.

Please mark brainliest

<em><u>Hope this helps.</u></em>

8 0
3 years ago
Weights of cars passing over a bridge part 2<br>​
DaniilM [7]

Step-by-step explanation:

The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.

Given:

mean,  mu = 3550 lbs (hope I read the first five correctly, and it's not a six)

standard deviation, sigma = 870 lbs

weights are normally distributed, and assume large samples.

Probability to be estimated between W1=2800 and W2=4500 lbs.

Solution:

We calculate Z-scores for each of the limits in order to estimate probabilities from tables.

For W1 (lower limit),

Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069

From tables, P(Z<Z1) = 0.194325

For W2 (upper limit):

Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954

From tables, P(Z<Z2) = 0.862573

Therefore probability that weight is between W1 and W2 is

P( W1 < W < W2 )

= P(Z1 < Z < Z2)

= P(Z<Z2) - P(Z<Z1)

= 0.862573 - 0.194325

= 0.668248

= 0.67 (to the hundredth)

6 0
3 years ago
Is negative 5/8ths more than,less than or equal to 0.27?
ollegr [7]
It is less than. Any negative number compared to a positive number will be less than.
7 0
2 years ago
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