Answer:
sin²x = (1 - cos2x)/2 ⇒ proved down
Step-by-step explanation:
∵ sin²x = (sinx)(sinx) ⇒ add and subtract (cosx)(cosx)
(sinx)(sinx) + (cosx)(cosx) - (cosx)(cosx)
∵ (cosx)(cosx) - (sinx)(sinx) = cos(x + x) = cos2x
∴ - cos2x + cos²x = -cos2x + (1 - sin²x)
∴ 1 - cos2x - sin²x = (1 - cos2x)/2 ⇒ equality of the two sides
∴ (1 - cos2x) - 1/2(1 - cos2x) = sin²x
∴ 1/2(1 - cos2x) = sin²x
∴ sin²x = (1 - cos2x)/2
Answer: plz report i'm trying to delete my account?!?!
Step-by-step explanation:
26/52 because reducing like terms gives us half compared to 21/49 being way less than half based on adding the numerators of these 2 fractions.
Answer:
![\frac{3b\sqrt[3]{c^{2}} }{a^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B3b%5Csqrt%5B3%5D%7Bc%5E%7B2%7D%7D%20%7D%7Ba%5E%7B2%7D%20%7D)
Step-by-step explanation:
∛(27a⁻⁶b³c²)
To simplify, first apply the cube root the each of the terms. Keep in mind this rule: ![\sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m} = a^{m/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%7D%20%20%3D%20%28%5Csqrt%5Bn%5D%7Ba%7D%29%5E%7Bm%7D%20%3D%20a%5E%7Bm%2Fn%7D)
∛27 = 3 (because 3*3*3 = 27)
∛a⁻⁶ = 
= 
= 
∛b³ = 
= 
= b
∛c² = 
∛(27a⁻⁶b³c²)
=
Simplified form generally follows these rules:
No negative exponents
No fraction exponents
Keep in fractional form
Reduce numerical values
