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2 years ago

Identify the terms, coefficients, and constants in the expression $18x+7$ .

Mathematics

1 answer:

BartSMP [9]2 years ago

4 0

Coefficients: 18
Constants: 7
Variable (if u need help on this): X

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Write an equation of the line in slope-intercept form.

Stels [109]

Answer:

Step-by-step explanation:

Y-intercept is -2.

Using slope formula, 2-(-2)/2-0 = 4/2 = 2 = slope.

Plugging into slope-intercept form:

y=mx+b => y=2x-2

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1 year ago

A cube has a side length of 14 M what is the volume of the cube

liraira [26]

<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ volume = length x width x height

Since it is a cube, all sides are equal

volume = 14 x 14 x 14

volume = $2744m^{3}$

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3 0

3 years ago

Read 2 more answers

What is the value of x after these statements if the starting value of x is 3.

kolbaska11 [484]

[A]
$3^{2}=9$
$5^{3}=125$
$9\neq25$

Ignore

[B]
$3^{2} = 9$
$9 \ \textgreater \ 3$
Yes

$3^{3}=27$
$4( 3^{2})=36

27 \ \textless \ 36$
Yes

Therefore
$x=3+2=5$

[C]
$4^{5}=1024

 5^{4}=625

1024\ \textless \ 625$
No

$5^{5}=3125

 5^{5}=3125

3125\ \textgreater \ 3125$
No

Ignore

[D]
$5^{5}=3125

 2^{5}=32

3125\ \textgreater \ 32$
Yes

$5^{2}=25
25\ \textless \ 11$
No

Therefore
$x=5+8=13$

[E]
$8\ \textgreater \ 7$
Yes

Therefore
$x = 13^{2}=169$

4 0

2 years ago

PLZ, help me with this question.

Korolek [52]

Answer:

Intensity

Step-by-step explanation:

In physics, intensity of radiant energy is the power transferred per unit area, where the area is measured on the plane perpendicular to the direction of propagation of the energy.

8 0

2 years ago

Read 2 more answers

Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and

SVEN [57.7K]

Answer:

B. 18

Step-by-step explanation:

For the function

$f(x)=\left\{\begin{array}{l}x+9,\ \ x$

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For $x$

$\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18$

2. For $x\ge 9:$

$\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18$

So, limit exists and is equal to 18.

8 0

2 years ago