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Leni [432]
3 years ago
8

Simplify the given expression below 2 over 2+5i

Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0
First, we can write this as a fraction:
2/(2+5i)
Then, we need to rationalize the fraction. This means that i is not present in the bottom of the fraction. To do this, we can multiply the numerator and denominator by (2-5i). This is because when multiplied by the numerator, a quadratic will be created when i is squared to create negative 1, and the other terms with i cancel each other out. You will see this in a moment.
2(2-5i)/(2+5i)(2-5i)
Then, distribute. Make sure to FOIL the bottom. This gives you:
(4-10i)/(4+10i-10i-25i^2)
The terms 10i and -10i cancel each other out, leaving us with:
(4-10i)/(4-25i^2)
Since i is the square root of negative 1, squaring it will give us -1. Thus, we have:
(4-10i)/(4+25)
And simplifying further:
(4-10i)/29
Sometimes, you are asked to write it in a+bi form, meaning you split it into two fractions. It looks like this:
(4/29) - ((10i)/29), or (4/29) - (10/29)i
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What is the fraction (in simplest form) for 420%? Thanks for the help
Lerok [7]
420/100= 42x10/10x10=
42/10=
2x21/2x5=
21/5
3 0
4 years ago
Tell whether the ordered pair is a solution to the equation.<br><br> (4, 4); y = -x + 8
ivann1987 [24]

Answer:

Yes, it is.

Step-by-step explanation:

(4) = -(4)+8

4=4

True

8 0
2 years ago
Select the correct answer.
Phantasy [73]
OB. h(Z) = 412 is the answer
3 0
3 years ago
A container in form of a frustum of a cone is 16 cm in diameter at the open end and 24 cm diameter at the bottom. If the vertica
Nat2105 [25]

Answer:

The capacity of the container is 2546.78 cm³.

Step-by-step explanation:

The volume of the frustum of a cone is:

\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]

The information provided is:

r = 16/2 = 8 cm

R = 24/2 = 12 cm

h = 8 cm

Compute the capacity of the container as follows:

\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]

            =\frac{\pi\cdot8}{3}\cdot[(12)^{2}+(12\cdot 8)+(8)^{2}]\\\\=\frac{8\pi}{3}\times [144+96+64]\\\\=\frac{8\pi}{3}\times304\\\\=2546.784445\\\\\approx 2546.78

Thus, the capacity of the container is 2546.78 cm³.

5 0
3 years ago
A merchant wishes to blend 200 pounds of coffee worth $3.20 a pound from two mixtures: one at $3.00 a pound and the other at $3.
Fofino [41]
X pounds of $3
y pounds of $3.25

x+y = 200

300x + 325y = 320*200
300x + 325y = 64000

x+y =200
300x +325y =64000

Solve by eliminating

Multiply top one w/-300

-300y =60000
325y=64000
25y = 4000

y= 160 then

x + 160= 200

x = 40


So the mixture has;

40 pounds of $3 coffee
160 pounds of $3.25 coffee






8 0
4 years ago
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