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stealth61 [152]
3 years ago
13

Help. find exterior angle.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
3 0
Let x be the measure of the exterior angle.
In the triangle,
using angle sum property, we have,
t + (t + 10) + (t + 20) = 180
=> t + t + 10 + t + 20 = 180
=> 3t + 30 = 180
=> 3t = 180 - 30
=> t = 150/3
=> t = 50

t° = 50°
(t+10)°= (50 + 10)° = 60°
(t+20)° = (50 + 20)° = 70°

now,
x° = (t+10)° + t° [by exterior angle property]
= 60° + 50°
= 110°
therefore the measure of the exterior angle is 110°
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Known facts:

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Variables:

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Set equation based on known facts and variables:

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Hope that helps!

7 0
2 years ago
The problem is in the picture.
Semmy [17]

Answer:

  • an = 5 + 10(n -1)
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Step-by-step explanation:

The explicit formula for the n-th term of an arithmetic sequence is ...

  an = a1 + d(n -1)

where a1 is the first term and d is the common difference.

The sequence of seat counts has a1=5 and d=10, so the explicit formula is ...

  an = 5 +10(n -1)

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The 7th term is ...

  a7 = 5 +10(7 -1) = 65

5 0
3 years ago
The average weight of the top 5 fish at a fishing tournament was 13.6 pounds. Some of the weights of the
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6 0
3 years ago
In 2008, data from the Center for Disease Control revealed that 28.5% of all male teenagers, aged 18-19 and attending U.S. colle
m_a_m_a [10]

Answer:

a) H0 : u = 28.5%

H1 : u < 28.5%

b) critical value = - 1.645

c) test statistic Z= - 1.41

d) Fail to reject H0

e) There is not enough evidence to support the professor's claim.

Step-by-step explanation:

Given:

P = 28.5% ≈ 0.285

X = 210

n = 800

p' = \frac{X}{n} = \frac{210}{800} = 0.2625

Level of significance = 0.05

a) The null and alternative hypotheses are:

H0 : u = 28.5%

H1 : u < 28.5%

b) Given a 0.05 significance level.

This is a left tailed test.

The critical value =

-Z_0.05 = -1.645

The critical value = -1.645

c) Calculating the test statistic, we have:

Z = \frac{p' - P}{\sqrt{\frac{P(1-P)}{n}}}

Z = \frac{0.2625 - 0.285}{\sqrt{\frac{28.5(1-28.5)}{800}}}

Z = -1.41

d) Decision:

We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645

e) There is not enough evidence to support the professor's claim that the proportion of obese male teenagers decreased.

5 0
3 years ago
Help plssssssssssssss
SIZIF [17.4K]
The answer is 140

140 x 0.1 (10% as a decimal) = 14
3 0
3 years ago
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