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pogonyaev
1 year ago
12

Can you explain to me how to do number two I'm studying for a quiz and I'm stuck on this one.

Mathematics
1 answer:
Furkat [3]1 year ago
5 0

we have (-3,10) and (7,4), then

\begin{gathered} (\frac{x1+x2}{2},\frac{y1+y2}{2}) \\ (\frac{-3+7}{2},\frac{10+4}{2}) \\ (\frac{4}{2},\frac{14}{2}) \\ (2,7) \end{gathered}

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Pls help for this question! no wrong answers pls
ankoles [38]

Answer:

41.29 cm²

Step-by-step explanation:

From the question,

Area of the shaded portion = Area of the circle - area of the square.

A' = πr²-L²...… Equation 1

Where A' = Area of the shade portion, r = radius of the circle, L = length of the square, π = pie

Given: r = 4 cm, L = 3 cm

Constant: π = 22/7.

Substitute these values into equation 1

A' = [(22/7)×4²]-3²

A' = 50.29-9

A' = 41.29 cm²

Hence the area of the shaded portion is 41.29 cm²

8 0
3 years ago
Please help me answer this question
Oliga [24]

Answer:

B

Step-by-step explanation:


7 0
3 years ago
Which is the graph of<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20-%202" id="TexFormula1" t
Anna11 [10]

ANSWER

See attachment.

EXPLANATION

The given function is

y =  \sqrt[3]{x + 1}  - 2

The parent function is

y =  \sqrt[3]{x}

When we shift the parent graph to the left one unit, and down 2 units, we obtain the graph of the given function.

The graph of this function is shown in the attachment.

5 0
3 years ago
The low temperatures for 5 days was 5, -2, -11 ,0 and-3.What was the average low temperature for those days
Daniel [21]
Data:
Average (A): ?
Arithmetic mean (A.M) = 5, -2, -11, 0, -3sum of n numbers = 5

Solving:
A = \frac{AM}{n} = \frac{5+(-2)+(-11)+0+(-3)}{5} = \frac{5-2-11-3}{5} = \frac{\diagup\!\!\!\!3-11-\diagup\!\!\!\!3}{5} = \frac{-11}{5} = - 2.2

Answer:

<span>The average low temperature of these days is -2.2</span>

3 0
3 years ago
If 3 pipes can fill the tank completely in 2 hour then when will 1 pipe fill the tank​
Montano1993 [528]

Answer:

6 hours

Step-by-step explanation:

8 0
3 years ago
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