Answer: The required value of y is 19.
Step-by-step explanation: We are given to find the value of y in the solution to the following system of equations :

Comparing equations (i) and (ii), we get

From equation (i), we get

Thus, the required value of y is 19.
the length of the side of this square is
cm
Answer:
Solutions Given:
let diagonal of square be AC: 8 cm
let each side be a.
As diagonal bisect square.
let it forms right angled triangle ABC .
Where diagonal AC is hypotenuse and a is their opposite side and base.
By using Pythagoras law
hypotenuse ²=opposite side²+base side²
8²=a²+a²
64=2a²
a²=
a²=32
doing square root on both side

a=±
a=±2*2
Since side of square is always positive so
a=4
or 5.65 cm
L=w+4 this shows the length is 4 inches longer than width
h=w-2 this shows the height is 2 inches shorter than the width
volume=lwh
so 240=lwh=(w+4)(w)(w-2)
simplify and solve to find the width then you can use that to find the other values as well.
11 because if you count the spaces between the two places, the answer would be 11.