Question

Use the given conditions to write an equation for the line passing through (-8,8) and parallel to the line whose equation is 5x-8y-7=0.

Answer 1

5x - 8y + 104 = 0 is a linear equation passing through (-8 , 8) and parallel to the line whose equation is 5x - 8y - 7 = 0.

First, for two equations of line to be parallel with each other, their slope must be equal.

Transforming the given equation into slope-intercept form, y = mx + b:

5x - 8y - 7 = 0

8y = 5x - 7

y = 5/8 x - 7/8

m = 5/8

Hence, the slope of our equation should also be 5/8.

Using the again the slope intercept form, solve for b.

y = mx + b

where m = 5/8, x = -8 and y = 8

8 = 5/8 (-8) + b

8 = -5 + b

b = 13

With m= 5/8 and y-intercept, b = 13, the equation of our line is

y = mx + b

y = 5/8 x + 13

Multiplying both sides by 8,

8y = 5x + 104

5x - 8y + 104 = 0

To know more about equation of line, brainly.com/question/13763238.

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