9514 1404 393
Answer:
117°
Step-by-step explanation:
We assume you want to report your bearing as an angle measured CW from North. For conventional angles greater than 90°, it will be ...
450° -angle = 450° -333° = 117°
The bearing of the ship is 117°.
The answer is 4) 140.
If we closely examine the pattern of the series, we see that after a number is subtracted by a value, it is multiplied by the same value, and then it moves on to the next natural number.
- 10 - 2 = 8
- 8 × 2 = 16
- 16 - 3 = 13
- 13 × 3 = 39
- 39 - 4 = 35
The next step, according to the pattern, would be to multiply 4.
Answer:
The answer is -13.
Step-by-step explanation:
=4×(-2)-5
=-8-5
=-13
The value of (-2) is -13.
<u>Question 1 solution:</u>
You have two unknowns here:
Let the Water current speed = W
Let Rita's average speed = R
We are given <em>two </em>situations, where we can form <em>two equations</em>, and therefore solve for the <em>two unknowns, W, R</em>:
Part 1) W→ , R←(against current, upstream)
If Rita is paddling at 2mi/hr against the current, this means that the current is trying to slow her down. If you look at the direction of the water, it is "opposing" Rita, it is "opposite", therefore, our equation must have a negative sign for water<span>:
</span>R–W=2 - equation 1
Part 2) W→ , R<span>→</span>(with current)
Therefore, R+W=3 - equation 2
From equation 1, W=R-2,
Substitute into equation 2.
R+(R–2)=3
2R=5
R=5/2mi/hr
So when W=0 (still), R=5/2mi/hr
Finding the water speed using the same rearranging and substituting process:
1... R=2+W
2... (2+W)+W=3
2W=1
W=1/2mi/hr
Answer:
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