Answer:
The raw score for his exam grade is 99.69.
Step-by-step explanation:
Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.
To find : What is the raw score for his exam grade?
Solution :
The formula use to find the z-score is
Where, z=1.67 is the z-score
is the means
is the standard deviation
x is the raw score for his exam grade
Substitute the values,
Therefore, the raw score for his exam grade is 99.69.
No solution to this problem
So the equation for these types of equations is f(x) = a(x-h)+k with h being a horizontal translation, a being a stretch/compression and k being a vertical translation. So here if you want a stretch of 4 a would be four, g(x)=4(-3x-h)+k. Also, there is a horizontal translation so it would be positive 4 into the equation. Since there is no change in the y-axis there is no vertical translation resulting in g(x) = 4(-3x-4)
Step-by-step explanation:
1075 students were asked how close they live to the college. The table shows the results below with some values missing. Enter the correct values in the boxes remembering to use the % symbol where necessary.
<u>20 to 25: </u>given 20%
20% of 1,075 = 215
<u>15 to 19: </u>given 12%
12% of 1,075 = 129
<u>10 to 14: </u>given 516 students
(516/1,075)*100 = 48%
<u>5 to 9: </u>given 162 students
(162/1,075)*100 = 15.07%
<u>< 5: </u>given 53 students
(53/1,075)*100 = 4.93%
Answer:
Where is the equation?
Step-by-step explanation:
