A. 45
Since the lines are parallel the angels are congruent
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
Answer:
if you need the formula, it is pq/2
Step-by-step explanation:
the "p" is a diagonal of the rhombus
the "q" is the other diagonal of the rhombus
you multiply p and q
the you divide that number by 2
then, you have found the area
Answer:
If he missed five questions he can get a zero
Step-by-step explanation:
Answer:
One is fraction and one is decimal
Step-by-step explanation:
