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Wewaii [24]
1 year ago
8

A jeweler had a fixed amount of gold to make bracelets and necklaces. The amount c

Mathematics
1 answer:
kvv77 [185]1 year ago
3 0

The jeweler made 7 bracelets and 9 necklaces .

In the question ,

it is given that

amount of gold in each bracelet is = 6 grams

amount of gold in each necklace is = 24 grams .

let the number of bracelets = "b" .

let the number of necklaces = "n" .

since the total number of necklace and bracelet is 16 .

the equation is b + n = 16

so , b = 16 - n

also given that total gold used is 258 grams .

so the equation is 6b + 24n = 258

Substituting b= 16 - n in the equation ,

we get , 6*(16 - n) + 24n = 258

96 - 6n + 24n = 258

96 + 18n = 258

18n = 258 - 96

18n = 162

n = 162/18

n = 9

and b = 16 - 9 = 7

Therefore , The jeweler made 7 bracelets and 9 necklaces .

Learn more about Equations here

brainly.com/question/10994155

#SPJ1

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