Ask question

Ask question

All categories

Mekhanik [1.2K]

3 years ago

14

A bucket contains one green block, one red block, and two yellow blocks. You choose one block from the bucket. Find the theoreti

cal probability that you will choose green.

1 answer:

Natali [406]3 years ago

7 0

Answer:

A)1/4, 1/2 ,1/4

B)1

C)3/4

D)1

Step-by-step explanation:

THESE IS THE COMPLETE QUESTION:

A bucket contains one green block, one red block, and two yellow blocks. You choose one block from the bucket.

A)Find the theoretical probability that you will choose each color.

B)Find the sum of probability in(a)

C)What is the probability that you will not choose a red block?

D)Find the sum of the probabilities of choosing a red block and probability of not choosing a red block

EXPLANATIONS:

Sample of blocks: green,red, yellow, yellow

Total sample =4

Green sample = 1

Red sample 1

Yellow sample = 2

A)To find the theoretical probability that you will choose green.

i) P( choosing a green block)= green sample/Total sample

=1/4

To find the theoretical probability that you will choose red

ii)P(choosing a red block) = Red sample block/Total sample of blocks

= 1/2

To find the theoretical probability that you will choose yellow

iii) P(choosing a yellow block) = 1/4

B)The sum of probability in( a)

=P( choosing a green block) + P( choosing a Red block) +P( choosing a yellow block)

= 1/4 + 1/2 + 1/4

=1

C)P( Not choosing a red block) = 1 - 1/4

= 3/4

D)P(Sum of choosing a red block and not choosing a a red block)

=1/4 + 3/4

= 1

You might be interested in

I’ve been trying to figure this out all day and still can’t seem to figure it out

Marat540 [252]

Answer:

(4x-1)(4x-1)

(x-6)(x+5)

(3x-7)(3x+7)

(3x-1)(x+6)

Step-by-step explanation:

yes

3 0

2 years ago

Find thhe remainder when 7^203 is divided by 4

Aleksandr [31]

Using the square-and-multiply approach, we have

$7^{203}=7\times(7^{101})^2$
$7^{101}=7\times(7^{50})^2$
$7^{50}=(7^{25})^2$
$7^{25}=7\times(7^{12})^2$
$7^{12}=(7^6)^2$
$7^6=(7^3)^2$
$7^3=7\times7^2$

and so, using the property that, if $a_1\equiv b_1\mod n$ and $a_2\equiv b_2\mod n$ , then $a_1a_2\equiv b_1b_2\mod n$ , we get

$7\equiv3\mod4$
$7^2\equiv9\equiv1\mod4$
$7^3\equiv7\times1\equiv7\equiv3\mod4$
$7^6\equiv9\equiv1\mod4$
$7^{12}\equiv1\mod4$
$7^{25}\equiv7\times1\equiv7\equiv3\mod4$
$7^{50}\equiv9\equiv1\mod4$
$7^{101}\equiv7\times1\equiv7\equiv3\mod4$
$7^{203}\equiv7\times9\equiv3\times1\equiv3\mod4$

4 0

3 years ago

4sinθ – 1 = - 3 for 0<θ< 360

EastWind [94]

Answer:

$\theta = 210^\circ$ or $\theta = 330^\circ$

Step-by-step explanation:

$4 \sin \theta - 1 = -3$

$4 \sin \theta = -2$

$\sin \theta = \dfrac{-2}{4}$

$\sin \theta = -0.5$

For sin θ = 0.5, the reference angle is θ = 30 deg.

$\sin 30^\circ = 0.5$

$\theta = 210^\circ$ or $\theta = 330^\circ$

7 0

3 years ago

In Argentina, a cow on a ranch is expected to need an average of 4200 m2

nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

$1 \: cow = 4200 \: {m}^{2}$

Then, for 4500 cows:

$4500 \: cows = 4200 \: {m}^{2} \times 4500$

$4500 \: cows = 18900000 \: m {}^{2}$

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

$1 \: hectare = 10000 \: {m}^{2}$

$x \: hectare = 18900000 \: {m}^{2}$

Then, putting them in proportion, We will get:

$x = \dfrac{18900000}{10000} hectares$

$x = \boxed{ 1890 \: hectares}$

So, the total area in hectares = <u>1</u><u>8</u><u>9</u><u>0</u><u> </u><u>hectares</u><u>.</u>

And we are done !!

#CarryOnLearning

<u>━━━━━━━━━━━━━━━━━━━━</u>

6 0

3 years ago

This is a really hard question- Help

kykrilka [37]

Answer:

680

Step-by-step explanation:

x = total number

.6x = bus riders = 408 (.6 is decimal for 60%)

.6x = 408

x = 408/.6 = 680

7 0

11 months ago